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When you are able to perform those miracles that means more followers in your church
All i will give is just a small …………. which you will wear or put on and the world start praising your name
My strength will provide Healing Powers to all manner of sicknesses and diseases, deliverance from satanic manipulations, perform miracles / wonders and rising above. It also attract Mass Wealthy Congregations to your Church / temple.
ARE YOU A PASTOR OR HEALER LOOKING FOR SPECIAL POWERS? ATTENTION: dear pastors and religious leaders , this is the ring that has turned many ministries and pastors lives today. It has helped many pastors get famous and churches gather lots of followers and not only followers but important people like government officials and big political leaders today , lots of synagogues and churches today are performing miracles and wonders , healing the sick by the help of this ring. The Ring also provides Healing Powers to all manner of sicknesses and diseases, deliverance from demonic manipulations, miracles and rising above.It empowers every word of your preaching to touch people’s hearts thus giving you a powerful magnetic personality. It is a very powerful Ring for one to build intuition power and foresee future .Very useful for person who does Speculation or Healing.
Pastors and Healers in many churches in Africa and Middle East are using this Fortune Teller Ring in their prophesying work. QUICKLY DELIVERIES ARE ALSO DONE ..

Are you a pastor, do you need power to perform miracles in your church, do you need to heal the people, make lame walk, make blind to see, make deaf people to hear, heal barrenness in women, and many more come to Professor . naseef to gain powers to perform those miracles
When you are able to perform those miracles that means more followers in your church
All i will give is just a small …………. which you will wear or put on and the world start praising your name
My strength will provide Healing Powers to all manner of sicknesses and diseases, deliverance from satanic manipulations, perform miracles / wonders and rising above. It also attract Mass Wealthy Congregations to your Church / temple.
ARE YOU A PASTOR OR HEALER LOOKING FOR SPECIAL POWERS? ATTENTION: dear pastors and religious leaders , this is the ring that has turned many ministries and pastors lives today. It has helped many pastors get famous and churches gather lots of followers and not only followers but important people like government officials and big political leaders today , lots of synagogues and churches today are performing miracles and wonders , healing the sick by the help of this ring. The Ring also provides Healing Powers to all manner of sicknesses and diseases, deliverance from demonic manipulations, miracles and rising above.It empowers every word of your preaching to touch people’s hearts thus giving you a powerful magnetic personality. It is a very powerful Ring for one to build intuition power and foresee future .Very useful for person who does Speculation or Healing.
Pastors and Healers in many churches in Africa and Middle East are using this Fortune Teller Ring in their prophesying work. QUICKLY DELIVERIES ARE ALSO DONE ..

Are you a pastor, do you need power to perform miracles in your church, do you need to heal the people, make lame walk, make blind to see, make deaf people to hear, heal barrenness in women, and many more come to Professor . naseef to gain powers to perform those miracles
When you are able to perform those miracles that means more followers in your church
All i will give is just a small …………. which you will wear or put on and the world start praising your name
My strength will provide Healing Powers to all manner of sicknesses and diseases, deliverance from satanic manipulations, perform miracles / wonders and rising above. It also attract Mass Wealthy Congregations to your Church / temple.
ARE YOU A PASTOR OR HEALER LOOKING FOR SPECIAL POWERS? ATTENTION: dear pastors and religious leaders , this is the ring that has turned many ministries and pastors lives today. It has helped many pastors get famous and churches gather lots of followers and not only followers but important people like government officials and big political leaders today , lots of synagogues and churches today are performing miracles and wonders , healing the sick by the help of this ring. The Ring also provides Healing Powers to all manner of sicknesses and diseases, deliverance from demonic manipulations, miracles and rising above.It empowers every word of your preaching to touch people’s hearts thus giving you a powerful magnetic personality. It is a very powerful Ring for one to build intuition power and foresee future .Very useful for person who does Speculation or Healing.
Pastors and Healers in many churches in Africa and Middle East are using this Fortune Teller Ring in their prophesying work. QUICKLY DELIVERIES ARE ALSO DONE ..
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Hi- I bought the book Cracking The Coding Interview. I am finding it hard to recreate these test practice questions in SAP ABAP language which is what I will be tested during my interview. Does anyone have any hints on this? I am not finding much resources online or even YouTube videos that describe how to prepare for this test using SAP ABAP. Thank you!

Cool Drink: Kenny loves Coca Cola.

- There are 'n' different shops in his colony from which he can buy coca cola.

- Each shop has different rate for the same coca cola bottle

- Kenny decided to buy his favorite cool drink for 'm' continuous days.

- Each day Kenny has 'p' money in his hand.

Find out from how many shops, Kenny can buy his favorite cool drink each day.

Prototype: Int[] find TotalShops(int input1, int[] input2 int input3, int] input4)

input1 - Total No. of shops in the colony
input2 - Rate of cool drink in each shop
input3 - No. of days, Kenny is going to buy the cool drink
input4 - Total money, Kenny has with him to buy cool drink, each day


output - No. of shops, in which, Kenny can buy cool drink, each day

Ex - input1 - 5
input2 - {3,10,8,6,11}
input3 - 4
input4 - {1,10,3,11}

output - {0,4,1,5}

write the functions char * reverse (char * nap, int n) - reverse the string nap except the character at position n (and its "symmetrical" equivalent) and return the inverted string as a result.
Example:

char tab[9]="abcdefgh";

cout << reverse(tab,3);

Output: hgfdecba // d is on same position

Hello,
I am 2019 passout from a tier 3 college with 9 months of experience right now. My coding skills are average and I work in Java.

Given an integer N, find the Nth number in the fibonacci series. Consider 0 and 1 to be the seed values. In a fibonacci series, each number ( Fibonacci number ) is the sum of the two preceding numbers. The series with 0 and 1 as seed values will go like- 0, 1, 1, 2, 3, 5… .

Input

The first line contains an integer T, depicting total number of test cases. Then following T lines contains an integer N.

Constraints:
1 ≤ T ≤ 50
1 ≤ N ≤ 50

Output

Space separated Nth fibonacci number for each N given in the input

You are asked q queries each of which can be of type 1 or type 2 Type 1 : Report the area of square of side S. Type 2 : Report the area of rectangle of sides L and R.

Input

The first line of the input contains single integer Q.
Next Q line contains the queries.
Each query first contains type of query
if query is of type one you are given a single integer S
if query is of type two you are given two integers L and R

Constraints
1 <= Q <= 25
1 <= T <= 2
1 <= S,L,R <= 1000

Output

Output Q line each containing answer to the asked query

Arrange the following growth rates in the increasing order.
O(n3),O(1),O(n2),O(nlogn),O(n2logn),Ω(n0.5),Ω(nlogn),Θ(n3),Θ(n0.5)

Hello Everyone, I want to know the functionality between vTable and vptr in C++. I have faced one interview on skype last week and Recruiter told me this question and i was not given the answer. I have checked on google to find it but still, I am confused. Can anyone know or suggest me some more c++ interview question. which is helpful for my upcoming interviews.

There is a function checkPassword() which takes a password and return an int which represents the number of correct characters at the correct position in that password.

Write a function findPassword() which takes a list of passwords and returns the correct password or null if it doesn't find the correct password. It can make calls to checkPassword() function but it is a very expensive function so the goal is to minimize the calls to checkPassword().

Assume all passwords are of same length.

Example:-
If correct password = abcd
calling checkPassword("axyz") would return 1

Sample Input =
String[] passwords = {"xxyz","axyz", "xbyz","abyz","axyd","xycd"}
System.out.println("password = "+findPassword(passwords));

Sample Output:-
password = abcd

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The webmail Bellsouth is the most popular emailing service that is offering the quality, unique, and amazing features for the users. Sometimes, users are passing through some technical problems with their account. A technical blunder is happening with me. I have forgotten my password of Bellsouth, hence I want to reset Bellsouth email password correctly. Resetting the password is a big challenge for me, hence I am getting stuck in the technical procedure. I don’t have the full technical skill on how to reset Bellsouth email password. Can anyone help for this technical blunder?

The question asks us to write a method that tells if one string is a permutation of the other. Looking at the solution it looks like the function tells if 2 strings are anagrams and not permutations. For example the function will return true for "dog" and "dgo". Am I missing something?

Given the code below. I need to replace all occurrences of List<List<Integer>> with List<PairInt>. I could not find this PairInt type/class in a library. Do I need to make a new class and what would that be? Thanks!

public static List<List<Integer>> getIdPairsForOptimal(List<List<Integer>> forwardList,
List<List<Integer>> backwardList, int maxDistance) {
List<List<Integer>> result = new LinkedList<List<Integer>>();
forwardList = forwardList.stream().sorted((x1, x2) -> Integer.compare(x2.get(1), x1.get(1)))
.collect(Collectors.toList());
backwardList = backwardList.stream().sorted((x1, x2) -> Integer.compare(x1.get(1), x2.get(1)))
.collect(Collectors.toList());
int maxDist = maxDistance;
while (true) {
for (List<Integer> l : forwardList) {
for (List<Integer> b : backwardList) {
int forward = l.get(1);
int backward = b.get(1);
int tot = (forward + backward);
if (tot > maxDist) {
break;
}
if (tot == maxDist) {
// print the pair of Id and optimum distance
result.add(Arrays.asList(l.get(0), b.get(0), maxDist));
break;
}

}
}
if (result.size() > 0) {
break;
}
maxDist--;
}
return result;
}

}

I was expecting a bi-directional search of question 1 in this chapter but found a single search in solution, Any reason?