Given a complete binary tree find if it is a value balanced tree or not.




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- Chutiye July 11, 2015 | Flag Reply
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bool isValueBalanced(int tree[],int count){
int loop,a,b;

loop=((count-1)/2) - 1;

while(loop != -1){
a=(2*loop) + 2;
b=2*loop+1;

if(tree[a] != tree[b])
{ return false;}
else{
tree[loop]=tree[loop] + tree[a]+tree[a];
loop--;
}

}
return true;

}

- Anonymous March 05, 2016 | Flag Reply
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bool isValueBalanced(int tree[],int count){
int loop,a,b;

loop=((count-1)/2) - 1;

while(loop != -1){
a=(2*loop) + 2;
b=2*loop+1;

if(tree[a] != tree[b])
{ return false;}
else{
tree[loop]=tree[loop] + tree[a]+tree[a];
loop--;
}

}
return true;

}

- Anonymous March 05, 2016 | Flag Reply
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C++ solution

bool isValueBalancedTree(size_t count, int *tree)
{
  int leftSum = 0, rightSum = 0;
  size_t n;

  tree++;   // First tree item [0] can be ignored
  count--;

  for (int halfElementsThisRow = 1; count; halfElementsThisRow *= 2, count -= halfElementsThisRow)
  {
    for (n = halfElementsThisRow; n--; )
      leftSum += *tree++;

    for (n = halfElementsThisRow; n--; )
      rightSum += *tree++;
  }

  return leftSum == rightSum;
}

- Luc September 10, 2018 | Flag Reply




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