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NVIDIA Interview Question


Country: United States



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12
of 12 vote

syntax error malloc takes only one argument.

- Anonymous January 25, 2012 | Flag Reply
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0
of 0 votes

yeahh I think the declaration needs to be char* buf = (char*) malloc(10 * sizeof(char));

- danielpiedrahita January 25, 2012 | Flag
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0
of 0 votes

type cast not required.

- Anonymous August 28, 2013 | Flag
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4
of 4 vote

1. Syntax error
2. Returning int, should return char*
3. Not returning size

- mag January 25, 2012 | Flag Reply
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0
of 0 votes

It would be good to specify what exactly the syntax error is. The thing that's definitely an error is the comma between 10 and sizeof. Many compilers will also complain about the implicit cast of char* to int.

- eugene.yarovoi January 26, 2012 | Flag
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0
of 0 votes

Error would be too many arguments into the malloc function

- learner@89 January 24, 2015 | Flag
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3
of 3 vote

char* error(){
	char* buf  = (char*)malloc(10*sizeof(char));
	return buf;

}

- m@}{ January 26, 2012 | Flag Reply
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0
of 2 vote

Compilation Fails.. Mismatch return type.. However, if you got a customized compiler to ignore such cases.. than No issue.. malloc won't create any issue.. However the programmer has to put the memory check for really allocations has happened or not.... Two rectification req..

- hprem991 January 25, 2012 | Flag Reply
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0
of 0 vote

OR

long error(){
	char* buf  = (char*)malloc(10*sizeof(char));
	return reinterpret_cast<long>(buf);

}

- m@}{ January 26, 2012 | Flag Reply
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0
of 0 votes

C doesn't have reinterpret_cast, and if it was C++, would have used new instead of malloc

- Dan June 01, 2012 | Flag
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0
of 0 vote

error: too many arguments to function malloc
warning : return makes integer from pointer without cast

- Santosh Diwase March 02, 2012 | Flag Reply
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0
of 0 vote

Error() Function returning an address.. is wrong....
The main function (calling function) will fail at runtime because buf goes out of scope , after error () function returns

- dss.chandra March 07, 2012 | Flag Reply
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0
of 0 votes

Its valid to return a pointer from malloc(). You're thinking of the error of returning a pointer to a local automatic variable.

- Dan June 01, 2012 | Flag


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