Interview Question for Software Engineer / Developers


Country: India
Interview Type: In-Person




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recursive loop is quite evident.. this is as per virtual call mechanism B::fun()
will get called and will kip on printing "B's f() called" till stack memory exhaust.

the Seg fault is due to stack full.

- anand.k.prasad February 28, 2012 | Flag Reply
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When foo() is being called first, compiler has to keep the every stack and finally, stack overflow.
In second case, your compiler is doing tail optimization and has freedom to drop the stack for previous recursive call. That's why it goes into a infinite loop because there is no stack overflow.

- Sudhir Tiwari March 08, 2012 | Flag
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Sudhir..Excellent explanation

- BJ September 15, 2012 | Flag
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Seg fault will happen even in second case.
In second case its bit delayed because of print statement, wait for 10 min. you will get Seg fault.

Anyway, what is "tail optimization" ?

- PK August 13, 2013 | Flag Reply
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RIP english

- Sirius April 28, 2014 | Flag Reply


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