Adobe Interview Question for Developer Program Engineers


Country: India
Interview Type: In-Person




Comment hidden because of low score. Click to expand.
0
of 0 vote

this can be done using a static bool variable
lets say the mutex has to be around task f1()
void mutex()
{
static bool bMutexVal = false;

}

- abc July 04, 2012 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

this can be done using a static bool variable
lets say the mutex has to be around task f1()
void mutex()
{
static bool bMutexVal = false;
if(bMutexVal ) return ;
bMutexval=true;
/* task to be done */
bMutexVal = false;
return;
}

- Anonymous July 04, 2012 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

improving Anonymous idea

Using Binary Semaphore bMutex where
false means no thread has acquired.
true means thread has acquired a lock.

static bool bMutex = false;
int Signal()
{
	if( bMutex == false)
	{
		bMutex = true;
		return 1;
	}
	else
	{
		WaitforSignal();
	}
}


//Thread will release the lock and go to sleep mode untill signalled
int Wait()
{
	if( bMutex == true)
	{
		bMutex = false
	}	
	SignalWaitingThreads();
	return 1;
}

This pseudo code could be improved

- Arulmozhi July 05, 2012 | Flag Reply


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