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Interview Question


Country: United States



Comment hidden because of low score. Click to expand.
1
of 1 vote

sizeof (p) is showing the size of char *p , you can check , do not initialise it , still it will show sizeof(p) as 4 and the sizeof("abcd") is showing the size of string abcd + null character.

- A. July 05, 2012 | Flag Reply
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0
of 0 votes

By the way, the correct way to get the length of the string would be

char p2[]="abcd";
sizeof(p2);

In the original example, p decays to a pointer, so sizeof(p) gives the size of the pointer; whereas p2 doesn't decay to a pointer and gives the size of the string.

- Anonymous July 08, 2012 | Flag
Comment hidden because of low score. Click to expand.
1
of 1 vote

sizeof(p) is the size of the pointer. It's not necessarily 4. On 64 bit machines, it'll be 8.

- Anonymous July 05, 2012 | Flag Reply
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0
of 0 vote

and sizeof(*p) is 1.
for sizeof, *p will point to the first character, and not the string.

- Anon July 05, 2012 | Flag Reply
Comment hidden because of low score. Click to expand.
-1
of 1 vote

Since the sizeof(p)=4 , whereas sizeof("abcd")=5
Explain it .

- Shobhit July 05, 2012 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

Because:
1).p stores address of something.A variable that stores address of something(integer,char,etc etc) is a pointer and has size =4;i.e sizeof(p)=4;(or 8 on 64 bit machines)
2)"abcd"is still a null terminated string(array of characters) in memory.hence has size 5;

- I want to code July 05, 2012 | Flag


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