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This is what I found from Oracle Website-

"If your class claims to implement an interface, all methods defined by that interface must appear in its source code before the class will successfully compile."

Answer to your question:
Class C will compile and run successfully. No error it works fine

As method max() has same signature in both Interfaces, we'll treat it as a single abstract method and define it only once.
Compiler will check if you implemented the methods declared in Interfaces.
As per the contract you did.

There is no question of Run time error as Interface doesn't have definition of method max()

Works fine.

interface A
{
void m();
}
 
interface B
{
void m();
}
 
class Test implements A,B
{
        public void m()
        {
                System.out.println("Done");
        }
 
        public static void main(String[] args)
        {
                Test t=new Test();
                t.m();
        }
}

At least in C#, it will compile and run just fine.
When implementing an interface, you need to comply with the method headers that are defined in the interfaces. If you implement 2 interfaces, then as long as you implement the methods (headers can be the same), then you're just fine.

For instance, the following will compile and run just fine:

class Program
    {
        static void Main(string[] args)
        {
            C c = new C();
            c.f(); //this will run just fine, and type bbbb
        }
    }

    interface A
    {
        void f();
    }

    interface B
    {
        void f();
    }

    class C : A, B
    {
        public void f()
        {
            Console.WriteLine("bbbb");
        }
    }

Interface is contract ! If any class implements any interface they just are supposed to implements all the methods with same signature which satisfies the contract.

Here is this case the implemented does satisfied A, B contract and thus it will not be any problem.

there is no problem in compiling and running this code with java

public interface A {
void m();
}


public interface B {
void m();
}


public class mainTest {
public static void main(String []args)
{
Test t = new Test();
t.m();
}

}


public class Test implements A,B {

@Override
public void m() {
// TODO Auto-generated method stub
System.out.println("University Of Delhi , India");

}

}

i thnik it will give runtime exception .we have to give alias of the interfaces so that particular method will be called for particular interface

its 100% Compilation error because JAVA doesn't support multiple inheritance so it will get the compilation error.

yeah there is no issue with this code in c#


using System;

public interface IA
{
void m();
}

public interface IB
{
void m();
}

public class Program : IA,IB
{
public void m()
{
Console.WriteLine("hello");
}

public static void Main()
{
Program p = new Program();
p.m();
}
}