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It's not possible to get the exact value back. >>> is not a reversible operation. In other words, there are multiple inputs such that applying >>> 2 to them would give you 24. 99, 98, 97, and 96 all yield 24. So if all you know is that you got an answer of 24, you won't be able to determine which of those you started with.

Very simple :
Java code is as follows :
public static void main(String[] args) {
int x = 99;
int y = 24;

int k = x ^ y;
System.out.println(" XOR ::"+k);
System.out.println(" To get 99 :: "+(k^24));
}

Very simple :
Java code is as follows :
public static void main(String[] args) {
int x = 99;
int y = 24;

int k = x ^ y;
System.out.println(" XOR ::"+k);
System.out.println(" To get 99 :: "+(k^24));
}

While shifting right by 2 , you have to store the bits you are going to loose after this operation. You have 24 , do left shift operation by 2 , you will get some value , OR it by the bits you have lost. you will get the answer.

Cisco gives hike once in 2-3 years.

New-Joinees only get hike after 2-3 years, so take 100% hike at the time of joining .. . otherwise don't cry after joining. :)

Cisco gives hike once in 2-3 years.

New-Joinees only get hike after 2-3 years, so take 100% hike at the time of joining .. . otherwise don't cry after joining. :)

Any Problem with this?

int n= 99999;
int x = n>>>1;
int y = x << 1;
int lsb = n & 1;
int number = y | lsb;