CareerCup

2 ptrs. 1 read - another write.
Read is faster than write. read reaches EOString - write a \0 in the write ptrs location.

char * findstr(const char * str)
         {   char *p;
             while(*str)
                  {
                    if(*str=='0')str++;
                    elseif
                       (*ptr)++=(*str)++;
                }
          return p;
         }

i am new to programming...i've a question for hopebasedcoder..can you please check again ur solution where
index++;i++;
}
str[index++]=str[i++];

check against "abc " if u can produce "abc"..m i missing something?

oh sorry got it...

public class DeleteSpacesFromAString {

public static void main(String args[]) {

String s = "fffg f f f f f f ffff ff";
boolean flag = true;
StringBuilder sb = new StringBuilder();
for (int i = 0; i < s.length(); i++) {
if (s.charAt(i) == ' ' && flag) {
flag = false;
sb = sb.append(s.charAt(i));
} else if(s.charAt(i) != ' ')
{
flag = true;
sb = sb.append(s.charAt(i));
}
}

System.out.println(sb.toString());

}
}

Can't we remove all spaces, and put one space at the end of the string, just before the end of string character.

removeWhiteSpace(char a[])
{
    int tail=0; 
    while(a[tail]!=' ')
         tail++;
       
    for(int i =tail;i<a.length;i++)
    {
         if(a[i]!= ' ')
         {
           a[tail]=a[i];
            tail++;
         }
    }
}

What if the given string contains tabs in it ?