CareerCup

Simply convert 'n' to a base-26 number. Each digit maps to a letter.

void f(int n)
{
if(n == 0)
return;
f((n-1)/26);
printf("%c", ((n-1)%26+'A'));
}

temp=temp1=n;
while(temp>0) // Find no of characters string will contain
{
no_of_char++;
temp=temp-pow(26,no_of_char);
}
str = (char *)malloc(no_of_char+1);// Dynanically Allocate the buffer

while(temp1>0)
{
temp= temp1 %26; // To find no with respect to alphabet
if(temp!=0)
str[next_char_index++]=temp+65-1;
else
{ // When modulas = 0 we know it is Z(since 26)
str[next_char_index++]='Z';
temp1--;
}
temp1= temp1/(26); // divide by 26 for next pass
}
str[next_char_index]='\0'; // Terminate string with NULL character
strrev(str); // since the characters are stored in reverse manner

can you post the questing elaborately?
What are the things that we need to find out.

#include <stdio.h>

int main(){
int rownum = 2842 ;
int i = rownum ;
int j = i ;
int count = 0 ;
int power = 0 ;

while(i >=26){
j = i ;
count = 0 ;
power = 1 ;
while(j >=26){
count++ ;
j = j/26 ;
}
printf("%c", 'A'+ j - 1) ;

for(j = 1 ; j <= count; j++){
power = power*26 ;
}
i = (i % power) ;
}
printf("%c\n", ('A' + i)) ;

return 0 ;
}

public void printSeries(int n) {
		int qt = n / 26;
		qt--;
		int rem = n % 26;
		rem--;
		char[] alpha = new char[26];
		char a = 'A';

		for (int i = 0; i < 26; i++) {
			alpha[i] = (char) a;
			a++;
		}

		String out = "";

		if (rem == -1) {
			qt--;
			rem = 25;
		}

		if (qt >= 0) {
			out = out + alpha[qt];
		}

		if (rem >= 0) {
			out = out + alpha[rem];
		}

		System.out.println(qt + " " + rem);
		System.out.println(out);
	}

{{def convertToTitle(num):
"""
:type n: int
:rtype: str
"""
result = ''
while num:
result = chr(ord('A') + (num-1)%26) + result
num = (num - 1)/26
return result

num= 29
convertToTitle(num)
output : AC}}

Python Solution

def convertToTitle(num):
    """
    :type n: int
    :rtype: str
    """
    result = ''
    while num:
        result = chr(ord('A')  + (num-1)%26) + result
        num = (num - 1)/26
    return result
    
num= 29
convertToTitle(num)

Output : AC