CareerCup

I believe this is an application of the classic velocity formula:

distance = velocity * time

If that is the case, the setup for the solution is as follows:

x = 2 * a
x = 10 * b
x = 20 * c
x = t * (a + b + c)

The "velocity" of each machine is its processing speed, indicated by a, b, and c above. The "distance" is the amount of effort, that is, x above. With that setup:

10 * b = 2 * a,     b = 1/5 * a
20 * c = 2 * a,     c = 1/10 * a

2 * a = t * (a + 1/5 * a + 1/10 * a)
2 * a = t * (10 * a + 2 * a + 1 * a) / 10
2 * a = t * 13/10 * a
2 = t * 13/10
20 / 13 = t

So the answer is 20/13 units of execution time.

Seems to be same sort of .....
one person can finish painting a house in 6 days, another in 4 days. if they work together, how long would it take to finish painting?

Answer comes out to be same as "Me" i,e 20/13 units of execution.

task with x efforts = assume a house with say 100 walls

person A finishes in 2 units of execution, means 2 days, so paints 50 walls in 1 day
person B finishes the same in 10 units of execution, means 10 days, so paints 10 walls in 1 day.
person C finishes the same in 20 unit of execution, means 20 days, so paints 5 walls in 1 day.

If all all work together for the same house, then in one day all paint, 50+10+5=65 walls

So to paint 100 walls they require 100/65 days = 20/13 days or say unit of execution.
x taxk

testing

1 / ((1/2) + (1/10) + (1/20)) = 20/13

Didnt we solve such questions in class 9 elementary algebra ?

yeah I guess this just explains that some companies just wanna know whether you got your basics right? its a good question to impress the interviewer :)

answer = 1/((1/day1) + (1/day2) + (1/day3) + ...)
       = 1/((1/2) + (1/10) + (1/20))
       = 20/13

btw, really nice question to check your basics ...

answer = 1/((1/day1) + (1/day2) + (1/day3) + ...)
       = 1/((1/2) + (1/10) + (1/20))
       = 20/13

btw, really nice question to check your basics ...

answer = 1/((1/day1) + (1/day2) + (1/day3) + ...)
       = 1/((1/2) + (1/10) + (1/20))
       = 20/13

btw, really nice question to check your basics ...

answer = 1/((1/day1) + (1/day2) + (1/day3) + ...)
       = 1/((1/2) + (1/10) + (1/20))
       = 20/13

btw, really nice question to check your basics ...

seems to be some problem with the submit option ...added 4 times, sorry guys..

the answer should be (X)*(20/13) and not plain 20/13. 20/13 is the speed with which the combined system executes tasks i.e. to say it can finish 20/13 tasks in 1 unit time.
All the above answers are wrong or incomplete at best I believe.

the answer should be (X)*(20/13) and not plain 20/13. 20/13 is the speed with which the combined system executes tasks i.e. to say it can finish 20/13 tasks in 1 unit time.
All the above answers are wrong or incomplete at best I believe.

the answer should be (X)*(20/13) and not plain 20/13. 20/13 is the speed with which the combined system executes tasks i.e. to say it can finish 20/13 tasks in 1 unit time.
All the above answers are wrong or incomplete at best I believe.

the answer should be (X)*(20/13) and not plain 20/13. 20/13 is the speed with which the combined system executes tasks i.e. to say it can finish 20/13 tasks in 1 unit time.
All the above answers are wrong or incomplete at best I believe.

the answer should be (X)*(20/13) and not plain 20/13. 20/13 is the speed with which the combined system executes tasks i.e. to say it can finish 20/13 tasks in 1 unit time.
All the above answers are wrong or incomplete at best I believe.

the answer should be (X)*(20/13) and not plain 20/13. 20/13 is the speed with which the combined system executes tasks i.e. to say it can finish 20/13 tasks in 1 unit time.
All the above answers are wrong or incomplete at best I believe.

the answer should be (X)*(20/13) and not plain 20/13. 20/13 is the speed with which the combined system executes tasks i.e. to say it can finish 20/13 tasks in 1 unit time.
All the above answers are wrong or incomplete at best I believe.