Microsoft Interview Question for Software Engineer / Developers






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perform bfs at each node with queue which maintains all the nodes that are visited by a single search. Also keep counter(level) for the node to determine level of the node.

- Darshan April 23, 2007 | Flag Reply
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Do a BFS with a queue.
Initially push the root and a null pointer on the queue.
Run a loop till the queue is empty.
pop the nodes out ..whenever we pop a null pointer increment the counter
and push a null pointer.

- Vamsi November 30, 2007 | Flag Reply
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Darshan is right, but it requires a little trick to maintain the size of the node in the current level

- Z December 29, 2008 | Flag Reply
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queue.enque(r);
c[0]=1; //store the children counts for each level.
t[0]=0;
tp=0;
while(queue.empty)
{
  NODE* n = queue.deque();
  t[tp]++;
  c[tp+1]+=n's children count;
  if(t[tp]==c[tp])
  {
    tp++;    
  }      

  queue.enque(n's children);
}

- jiangok2006 October 12, 2010 | Flag Reply


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