Bloomberg LP Interview Question for Financial Software Developers






Comment hidden because of low score. Click to expand.
1
of 1 vote

char str[] = "google";

for (int i = 0; i < strlen(str); ++i)
for (int j = 7; j >= 0; --j)
printf("%d", str[i]&(1<j) ? 1 : 0);

- Anonymous November 04, 2008 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

the last line should be printf("%d", str[i] & (1<<j) ? 1:0);

- Anonymous November 05, 2008 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

And maybe I'm wrong, but 'j' should not start at 7... it looks like j should start with a 1 in the 7th position; something like j = 0b1000000; isn't it?

- wihenao August 24, 2009 | Flag
Comment hidden because of low score. Click to expand.
0
of 0 vote

heres something different - not for production code :)

long long string = 0LL, mask = 1LL;
strcpy((char *)&string,"google");

for ( int i = 0; i < 48; ++i ) { // there are 48 bits in google
cout << ((string>>(63-i))&mask); // length of string is 64 bits
}

- acoader November 06, 2008 | Flag Reply


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