Bloomberg LP Interview Question for Financial Software Developers






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No, using pointers to call a function is just calling a function using pointer! ;)

Something like that:


class OurClass
{
  void a();
  void b();
  void c();
};

void OurClass::a()
{ printf"Ourclass.a()\n");}

void OurClass::b()
{ printf"Ourclass.b()\n");}

void OurClass::c()
{ printf"Ourclass c()\n");}

typedef void (OurClass::*OurClassMemberPointers)(int);
OurClassMemberPointers[3] = {&OurClass::a(), &OurClass::b(), &OurClass::c()};



inside "main":

OurClass x;
for(int i=0;i<3;i++)
   {
     OurClass* p = OurClassMemberPointers[i];
     (x.*p)(); // call the function by the pointer, i.e. a,d.c sequentially

   }

- sergey.a.kabanov January 13, 2012 | Flag Reply


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