CareerCup

One more thing, if you have embedded experience then do a thorough reading on OS concepts. they will try to confuse you to the core. Most of the time u will be knowing the answer but when u answer the question the expect a complete A-to-Z details about that topic...Be prepared for RTOS and basic OS concepts...Its very important

this wont copy '\0'

It shd return dest
take care like dest shd be replaced and has enough place

main()
{
char *p;
char *q,*temp;
p=(char*)malloc(50);
q=(char*)malloc(50);
temp=q;
strcpy(p,"this is string\0");
printf("%s \n",p);
while(*temp++ = *p++);
printf("%s \n",q);
return 0;
}
Output:
this is string
this is string

main()
{
char *p;
char *q,*temp;
p=(char*)malloc(50);
q=(char*)malloc(50);
temp=q;
strcpy(p,"this is string\0");
printf("%s \n",p);
while(*temp++ = *p++);
printf("%s \n",q);
return 0;
}
Output:
this is string
this is string

the simplest would be

char *strcpy(char *dst, const char *src)
  {
          char *rettmp = dst; ///return pointer
          ///pointer and len must have being validated prior invoking this function
          while ((*dst++ = *src++) != '\0')
                  /* nothing needs to be done, sometimes compiler optimizations can create problem but most versions of the gcc works fine*/;
          return rettmp;
  }

#include<stdio.h>
void main()
{
char *p,*q;
while((*p++=*q++) && (*q!='\0'));
}