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Barclays Capital Interview Question for Software Engineer / Developers






Comment hidden because of low score. Click to expand.
3
of 3 vote

should be 1 2 3 4 5.
i[a-i] <=> *(a-i+i) = *a = a[0] = 1
1%N = 1%5 = 1
1[a+i-1] <=> *(a+i-1+1) = *(a+i) = a[i]

haven't tried it though.

- ftfish July 25, 2010 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

You right.

- DRY July 25, 2010 | Flag
Comment hidden because of low score. Click to expand.
0
of 0 votes

How can u say that [a+i-1] = 1[a+i-1]????????

- Atulkumar June 28, 2012 | Flag
Comment hidden because of low score. Click to expand.
1
of 1 vote

its not like
[a+i-1] ==> 1[a+i-1]
but
1 comes from
(i[a-i] % N)[a+i-1]
(*(a-i+i) % N)[a+i-1]
( *a% N)[a+i-1]
( a[0]% N)[a+i-1]
( 1% N)[a+i-1]
(1%5)[a+i-1]
1[a+i-1]
*(a+i-1+1)
*(a+i)
a[i]

- Paras Patel November 07, 2012 | Flag
Comment hidden because of low score. Click to expand.
1
of 1 vote

Why in the world would someone use such cryptic syntax in production code?

- vick May 12, 2011 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

You sure you write it right?

- Anonymous July 25, 2010 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

Yes, sorry. Already corrected.

- fiddler.g July 25, 2010 | Flag
Comment hidden because of low score. Click to expand.
0
of 0 vote

std::cout << (i[a-i]%N)[a+i-1] << " ";

CAN ANY ONE PLS EXPLAIN THE ABOVE STATEMENT...I'M STILL NOT ABLE TO GET IT??

- SEEKER7 November 21, 2010 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

i don't quite understand the statement either, can someone who knows kindly explain it?

- K November 24, 2010 | Flag
Comment hidden because of low score. Click to expand.
0
of 0 vote

either arr[1] or 1[arr] -- both mean same

so, for example, the following code prints - 1 to 5

for(int j=0; j < 5; j++)
{
cout << endl << j[a] << endl;
}

hope this helps.

- siva January 28, 2011 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

It seems like recruiters are begging for someone to defecate in their offices.

- Anonymous February 15, 2012 | Flag Reply


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