Write an algorithm to convert

HCL America Interview Question for Solutions Architects

of 0 votes

1
Answer

Write an algorithm to convert string "1234.56" to its float equivalent.
Solution:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace MSIntervewPreparation
{
    class ConvertStringToFloat
    {
        static void Main(string[] args)
        {
            string str = "1234.56";
            float num = 0.0F;
            float multiplier = 0.1F;
            bool isDecimalReached = false;
            for (int i = 0; i < str.Length; i++)
            {
                if (str[i] == '.')
                {
                    isDecimalReached = true;
                    continue;
                }
                if (!isDecimalReached)
                {
                    num = (num * 10) + (str[i] - '0');
                }
                else
                {
                    num += (str[i] - '0') * multiplier;
                    multiplier *= 0.1F;
                }
            }
            Console.WriteLine("Input String: " + str);
            Console.WriteLine("Float Number: {0} ", num);
        }
    }
}

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Comment hidden because of low score. Click to expand.

of 0 vote

public static double StringToFloat(string s)
        {
            if (s == null || s.Length == 0)
                throw new InvalidStringException("Invalid String Entered");
            int length = s.Length;
            int i = 0;
            double lastNumber = 0;
            int returnNumber = 0;
            bool numberNegative = false;
            bool numberPositive = false;
            int startPoint = 0;
            int factor = 1;
            bool IsFloat = false;
            if (s[0] == '-')
            {
                numberNegative = true;
                startPoint = 1;
            }
            if (s[0] == '+')
            {
                numberPositive = true;
                startPoint = 1;
            }
            for (i = startPoint; i < length; i++)
            {
                if (s[i] == ' ')
                {
                    continue;
                }
                else if (s[i] == '.')
                {
                    IsFloat = true;
                    continue;
                }
                else
                {
                    if ((s[i] >= '0') && s[i] <= '9')
                    {
                        returnNumber = s[i] - '0';
                        if (i > 0) lastNumber = lastNumber * 10;
                        lastNumber = lastNumber + returnNumber;
                        if (IsFloat)
                            factor *= 10;
                    }
                    else
                    {
                        break;
                    }

                }
            }
            if (numberNegative)
                lastNumber = -1 * lastNumber;

            if (IsFloat)
                lastNumber = lastNumber / factor;

            return lastNumber;
        }

- manu November 04, 2010 | Flag Reply

Comment hidden because of low score. Click to expand.

of 0 votes

This code will work however for numbers with high precision (PI to the 20th digit) it will throw an exception since it builds an int and divides by a factor at the end.

- Reza August 22, 2015 | Flag

Comment hidden because of low score. Click to expand.

of 0 vote

java
// In Java
class StrToFloat {
    public static void main(String[] args) {
        String str = "1234.56";
        float n = 0;
        int intPartLength = str.length() - str.substring(str.indexOf('.')).length();
        for(int i = 0; i < intPartLength; i++) {
            n += (str.charAt(i) - '0') * Math.pow(10, (intPartLength - 1) - i);
        }
        for(int i = intPartLength+1; i < str.length(); i++) {
            n += (str.charAt(i) - '0') / Math.pow(10, (i - intPartLength+1)-1);
        }

        System.out.println(n);
    }
}

- Phil Fernandez October 27, 2020 | Flag Reply

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