N/A Interview Question for Software Engineer / Developers


Team: ERP
Country: India




Comment hidden because of low score. Click to expand.
3
of 3 vote

Here's O(1) solution in Python. Performs exactly what is requested and handles all edge cases in a robust way with 0 overhead. I exhaustively tested it on ALL possible inputs.

print "[1,5,6,3,7,2,8,9,4,10]"

Sorry, couldn't resist :)

- Visitor January 01, 2015 | Flag Reply
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0
of 0 votes

Lol

- Abhay January 04, 2015 | Flag
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0
of 0 votes

public class ArrayEx1 {

	/**
	 * @param args
	 * 
	 * Having a list of int [1,1,1,3,1,2,1,1,4,1]
	 * Output needed [1,5,6,3,7,2,8,9,4,10]
	 * without changing 2,3,4
	 * 
	 */
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		
		int[] a = {1,1,1,3,1,2,1,1,4,1};
		int len = a.length;
		System.out.println("Before Changing");
		for(int i : a){
		System.out.print(i+",");
		}
		int j = 5;
		for(int i=1;i<len;i++){
			if(a[i]<2){
				a[i]=j++;
			}
		}
		System.out.println();
		System.out.println("After Changing ");
		for(int k : a){
			System.out.print(k+",");
		}

	}

}

- Punto February 18, 2015 | Flag
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2
of 2 vote

Without much more description of what you're asking, I'm assuming that you mean to remove duplicate numbers in the array while preserving the original value when possible.
I can do this in O(n) with the following algorithm:
-Scan the array to figure out which numbers are already present
-for each number, replace it if necessary using a 1-upped counted value that skips already used numbers

public static void replaceDups(int[] arr){
	HashMap<Integer, Boolean> isSafe = new HashMap<Integer, Boolean>();
	for(int i : arr){
		isSafe.put(i, true);
	}
	
	int c = 1;
	for( int i = 0; i < arr.length; i++){
		Boolean isUsed = isSafe.get(arr[i]);
		if(!isUsed){
			while(used.containsKey(c)){
				c++;
			}
			arr[i] = c;
			c++;
		}
		else{
			isSafe.put(arr[i], false);
		}
	}
}

- zortlord December 31, 2014 | Flag Reply
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0
of 0 votes

Good job in decrypting the question first. :)

- Amit January 04, 2015 | Flag
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0
of 0 votes

public class ArrayEx1 {

/**
* @param args
*
* Having a list of int [1,1,1,3,1,2,1,1,4,1]
* Output needed [1,5,6,3,7,2,8,9,4,10]
* without changing 2,3,4
*
*/
public static void main(String[] args) {
// TODO Auto-generated method stub

int[] a = {1,1,1,3,1,2,1,1,4,1};
int len = a.length;
System.out.println("Before Changing");
for(int i : a){
System.out.print(i+",");
}
int j = 5;
for(int i=1;i<len;i++){
if(a[i]<2){
a[i]=j++;
}
}
System.out.println();
System.out.println("After Changing ");
for(int k : a){
System.out.print(k+",");
}

}

}

- Punto February 18, 2015 | Flag
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0
of 0 vote

Not knowing full description I can write this simple one:

public class Driver
{
public static void main(String[] ars)
{
int[] arr = {1,1,1,3,1,2,1,1,4,1};
int max = Integer.MIN_VALUE;

for (int val : arr)
{
max = (max < val) ? val: max;
}

for (int i=1; i<arr.length; i++)
{
if (arr[i] != 2 && arr[i] != 3 && arr[i] != 4)
{
arr[i] += max;
max = arr[i];
}
}

for(int val : arr)
{
System.out.print(val + " ");
}
} // end of main
} // end of class

- Ilgor January 01, 2015 | Flag Reply
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0
of 0 votes

public class ArrayEx1 {

/**
* @param args
*
* Having a list of int [1,1,1,3,1,2,1,1,4,1]
* Output needed [1,5,6,3,7,2,8,9,4,10]
* without changing 2,3,4
*
*/
public static void main(String[] args) {
// TODO Auto-generated method stub

int[] a = {1,1,1,3,1,2,1,1,4,1};
int len = a.length;
System.out.println("Before Changing");
for(int i : a){
System.out.print(i+",");
}
int j = 5;
for(int i=1;i<len;i++){
if(a[i]<2){
a[i]=j++;
}
}
System.out.println();
System.out.println("After Changing ");
for(int k : a){
System.out.print(k+",");
}

}

}

- Punto February 18, 2015 | Flag
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0
of 0 vote

#include<stdio.h>
#include<stdlib.h>

int main(int argc, char *argv[])
{
int list[] = {1,1,1,3,1,2,1,1,4,1};
int max= 0,i;
int len = sizeof(list)/sizeof(int);
for(i=0;i<len;i++)
{
        if(max<list[i])
        {
                max= list[i];
        }
}
for(i=1;i<len;i++)
{
        if(list[i] == 1)
        {
                list[i] = ++max;
        }
}
for(i=0;i<len;i++)
{
        printf("%d\n",list[i]);
}

return 0;
}

~                                                                                                                                                                                                            
~

- kshitiz gupta January 02, 2015 | Flag Reply
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0
of 0 vote

public class Logic {
void change(int a[])
{
int temp = 5 ;
int n = a.length;
for(int i = 1 ; i<n ; i++)
{
if(a[i]==3 || a[i]==2 || a[i]==4)
continue ;
a[i]= temp++ ;
}
}

public static void main(String args[])
{
Logic l = new Logic();
int a[]= {1 , 1 , 1 , 3 , 1 , 2 , 1 , 1 , 4 , 1};
int m = a.length ;
l.change(a);
for(int j=0 ; j<m ; j++)
System.out.print(" "+a[j]);

}
}

- vinod January 14, 2015 | Flag Reply
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0
of 0 vote

and

public static void main (String args[]) {
int input [] = new int[] {1,1,1,3,1,2,1,1,4,1};
int maxValue = 0;
// find max value
for (int i : input) {
if (i > maxValue) {
maxValue = i;
}
}
// core logic
Map<Integer, Integer> map = new HashMap <Integer, Integer> ();
int output [] = new int[input.length];
int counter = 0;
for (int i : input) {
if (map.get(i) == null) {
map.put (i, 0);
output [counter++] = i;
}
else {
output[counter++] = ++maxValue;
}
}
// print values
for (int i : output) {
System.out.print (i + " ");
}
}

and

- Dj January 19, 2015 | Flag Reply
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0
of 0 vote

int j=0;
int[] array = {1,1,1,3,1,2,1,1,4,1};
System.out.println(Arrays.toString(array));
for(int i=1; i<array.length; i++){
if(array[i] == 1){
array[i] = array[i]*5+j;
j++;
}else{
array[i] = array[i];
}
}
System.out.println(Arrays.toString(array));

- Rupa January 20, 2015 | Flag Reply
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0
of 0 vote

public class MakeConsecutiveList
{

public static void main(String [] args)
{
int [] arr={1,1,1,3,1,2,1,1,4,1};
int max=0;
for(int ele:arr)
{
if(ele>max)
{
max=ele;
}
}
for(int i=0;i<arr.length-1;i++)
{
for(int j=i+1;j<arr.length;j++)
{
if(arr[i]==arr[j] )
{
arr[j]=++max;
}
}
}
for(int ele:arr)
System.out.print(ele+" ");

}

- Pradeep kumar R S January 20, 2015 | Flag Reply
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0
of 0 vote

public static void removeDuplicatedByReplacingNextNumbers(int[] arr){
		
		HashMap<Integer, Boolean> map = new HashMap<Integer, Boolean>();
		int maxValue=0;
		
		for(int i=0;i<arr.length;i++){
			
			if(!map.containsKey(arr[i])){
				map.put(arr[i],false);
			}
			
			if(arr[i] > maxValue){
				maxValue = arr[i];
			}	
		}
		
		
		for(int j=0;j<arr.length;j++){
			if(!map.get(arr[j])){
				map.put(arr[j], true);
			}else{
				maxValue = maxValue+1;
				arr[j] = maxValue;
			}
		}
		
	}

- jimmy.sjsu January 26, 2015 | Flag Reply
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0
of 0 vote

public static void main(String[] args) {

		Integer a[] = { 1, 1, 1, 3, 1, 2, 1, 1, 4, 1 };

		LinkedList<Integer> ll = new LinkedList<Integer>();

		boolean found = false;
		int max = 0;

		for (int i = 0; i < a.length; i++) {
			max = max > a[i] ? max : a[i];
			if (!found) {
				if (a[i] == 1)
					found = true;
			} else {
				if (a[i] == 1) {
					ll.add(i);
				}
			}
		}

		while (!ll.isEmpty()) {

			a[ll.removeFirst()] = ++max;
		}

		System.out.println(Arrays.toString(a));

- Mithoon January 29, 2015 | Flag Reply
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0
of 0 vote

public class ArrayEx1 {

	/**
	 * @param args
	 * 
	 * Having a list of int [1,1,1,3,1,2,1,1,4,1]
	 * Output needed [1,5,6,3,7,2,8,9,4,10]
	 * without changing 2,3,4
	 * 
	 */
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		
		int[] a = {1,1,1,3,1,2,1,1,4,1};
		int len = a.length;
		System.out.println("Before Changing");
		for(int i : a){
		System.out.print(i+",");
		}
		int j = 5;
		for(int i=1;i<len;i++){
			if(a[i]<2){
				a[i]=j++;
			}
		}
		System.out.println();
		System.out.println("After Changing ");
		for(int k : a){
			System.out.print(k+",");
		}

	}

}

- Punto February 18, 2015 | Flag Reply
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0
of 0 vote

#include<iostream>
using namespace std;
int safe(int i,int count[])
{
for(int j=1;j<10;j++)
{
if(count[j]==0)
{
count[j]=1;
return j;
break;
}
}
}
int main()
{
int a[]={1,1,1,1,3,1,2,4,1};
int n=sizeof(a)/sizeof(a[0]);
int count[10]={0};
for(int i=0;i<n;i++)
{
count[a[i]]++;
}
cout<<a[0];
for(int i=1;i<n;i++)
{
if(count[a[i]]==1)
{
cout<<a[i];
}
else if(count[a[i]]>1)
{
int ind=safe(a[i],count);
cout<<ind;
}
}
}

- abc March 02, 2015 | Flag Reply
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0
of 0 vote

#include<iostream>
using namespace std;
int safe(int i,int count[])
{
for(int j=1;j<10;j++)
{
	if(count[j]==0)
	{
		count[j]=1;
		return j;
		break;
	}
}	
}
int main()
{
	int a[]={1,1,1,1,3,1,2,4,1};
	int n=sizeof(a)/sizeof(a[0]);
	int count[10]={0};
	for(int i=0;i<n;i++)
	{
	count[a[i]]++;	
	}
	cout<<a[0];
	for(int i=1;i<n;i++)
	{
		if(count[a[i]]==1)
		{
			cout<<a[i];
		}
		else if(count[a[i]]>1)
		{
			int ind=safe(a[i],count);
			cout<<ind;
		}
	}
}

- abc March 02, 2015 | Flag Reply
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0
of 0 vote

# list = [1,1,1,3,1,2,1,1,4,1]
# result = [1, 5, 6, 3, 7, 2, 8, 9, 4, 10]

list = [1,1,1,3,1,2,1,1,4,1]

hash = Hash.new(0)

list.each do |element|
  hash[element] += 1
end

i = counter = 1

while i < list.size
  if hash[list[i]] > 1
    until hash[counter].zero? do
      counter += 1
    end
    list[i] = counter
    counter += 1
  end
  i += 1
end

puts 'Result: ' + list.to_s

- Manoj April 26, 2015 | Flag Reply
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0
of 0 vote

public static void arrangeArrayWithBuffer(int[] a){
    	int max= Integer.MIN_VALUE;
    	Set<Integer> arraySet = new HashSet<Integer>();
    	for(int i=0; i<a.length; i++){
    		if(max<a[i])
    			max = a[i];
    	}
    	for(int i=0; i<a.length; i++){
    		if(!arraySet.add(a[i]))
    			a[i]= ++max;
    	}

}

- Anonymous May 08, 2015 | Flag Reply
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0
of 0 vote

public static void arrangeArrayWithBuffer(int[] a){
int max= Integer.MIN_VALUE;
Set<Integer> arraySet = new HashSet<Integer>();
for(int i=0; i<a.length; i++){
if(max<a[i])
max = a[i];
}
for(int i=0; i<a.length; i++){
if(!arraySet.add(a[i]))
a[i]= ++max;
}
}

- Guru May 08, 2015 | Flag Reply
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0
of 0 vote

public static void arrangeArrayWithoutBuffer(int[] a){
int max= Integer.MIN_VALUE;
for(int i=0; i<a.length; i++){
if(max<a[i])
max = a[i];
}
for(int i=1; i<a.length; i++){
for(int j=0; j<i ; j++){
if(a[i] == a[j]){
a[i] = ++max;
break;
}
}
}
}

- Guru May 08, 2015 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

/*
c language program
Linked list problem
input [1,3,1,4,1,1,6,]
output[2,3,3,4,4,5,6]
note:- only change 1 value given input
*/
#include<stdio.h>
#include<malloc.h>
int a=0;
struct Node{
int data;
struct Node *next;
}*head=NULL;
void insert(int);
void show();
main()
{
int value;
char choise='y';
while(choise=='Y'||choise=='y')
{
printf("\nEnter integer values:-");
scanf("%d",&value);
insert(value);
fflush(stdin);
printf("\nEneter another element (y/n):-");
scanf("%c",&choise);
}
show();
}
void insert(int value)
{
struct Node *temp=head,*element=(struct Node*)malloc (sizeof(struct Node));
element->data=value;
if(head==NULL)
{
element->next=head;
head=element;
}
else
{
while(temp->next!=NULL)
{
temp=temp->next;
}
temp->next=element;
element->next=NULL;
}
}
void show()
{
printf("\n");
struct Node *temp=head;
while(temp!=NULL)
{
if(temp->data==1)
{a++;
printf(" %d",(temp->data)+a);
}
else
printf(" %d",temp->data);
temp=temp->next;
}
}

- Nandu deshmukh January 07, 2016 | Flag Reply
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0
of 0 vote

/*
Linked list problem
input [1,3,1,4,1,1,6,]
output[2,3,3,4,4,5,6]
note:- only change 1 value given input
*/
#include<stdio.h>
#include<malloc.h>
int a=0;
struct Node{
int data;
struct Node *next;
}*head=NULL;
void insert(int);
void show();
main()
{
int value;
char choise='y';
while(choise=='Y'||choise=='y')
{
printf("\nEnter integer values:-");
scanf("%d",&value);
insert(value);
fflush(stdin);
printf("\nEneter another element (y/n):-");
scanf("%c",&choise);
}
show();
}
void insert(int value)
{
struct Node *temp=head,*element=(struct Node*)malloc (sizeof(struct Node));
element->data=value;
if(head==NULL)
{
element->next=head;
head=element;
}
else
{
while(temp->next!=NULL)
{
temp=temp->next;
}
temp->next=element;
element->next=NULL;
}
}
void show()
{
printf("\n");
struct Node *temp=head;
while(temp!=NULL)
{
if(temp->data==1)
{a++;
printf("  %d",(temp->data)+a);
}
else
printf("  %d",temp->data);
temp=temp->next;
}

}

- Nandu deshmukh January 07, 2016 | Flag Reply


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