Interview Question

Country: India

Comment hidden because of low score. Click to expand.
of 0 vote

Isn't it same as a palindrome check question? If yes, here is the java code:

public class Test {
    static boolean isPowerList(int[] arr){
        //Take 2 pointers- one starts forward from 0 and another starts from end backwards
        int i=0, j=arr.length-1;
        while (i<j){
            if (arr[i++] != arr[j--]){
                return false;
        return true;
    public static void main(String[] args) {
        int[] arr1 = {1,2,1};
        int[] arr2 = {1,2,3,4,5,6,7,6,5,4,3,2,1,1};
        int[] arr3 = {1,2,3,4,5,6,1000,6,5,4,3,2,1};
        System.out.println(isPowerList(arr1)); //true
        System.out.println(isPowerList(arr2)); //false
        System.out.println(isPowerList(arr3)); //true

- Pawan Kishor Singh October 17, 2020 | Flag Reply
Comment hidden because of low score. Click to expand.
of 0 vote

arr = map(list(int, input().rstrip().split()))
x = len(arr)
a = []
for i range(x//2):
if arr[i] == arr[x-i]:
if 0 in a:

- Npk.. October 20, 2020 | Flag Reply

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