Qualcomm Interview Question for Software Developers


Country: United States
Interview Type: Phone Interview




Comment hidden because of low score. Click to expand.
0
of 0 vote

#include <pthread.h>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int average;
int size = 0;

void *calcAvg(void *arg);
int numbers[] = {0,1,2,3,4,5,6,7};

pthread_mutex_t count_mutex = PTHREAD_MUTEX_INITIALIZER;
pthread_cond_t even = PTHREAD_COND_INITIALIZER;
pthread_cond_t odd = PTHREAD_COND_INITIALIZER;

void *print_even();
void *print_odd();
int count = 0;

// This is useful when the elements are not provided via array
#define COUNT_DONE 200


int main(int argc, char *argv[])
{
if(argc < 1)
exit(0);

//initialize an array of the integers to be passed
int numSize = atoi(argv[1]);
srand(time(NULL));
int *nums = (int*)malloc((numSize)*sizeof(int));
int i ;
for(i = 0; i < numSize ; i++)
{
nums[i] = (rand() % 100) + i ;
printf("%d " , nums[i]);
size++;
}
printf("\n");
//Thread Identifier
//pthread_t avgThread;
//pthread_create(&avgThread, NULL, calcAvg, (void*)nums);
pthread_t even_thread;
pthread_t odd_thread;
pthread_create(&even_thread, NULL, print_even , (void*)nums);
pthread_create(&odd_thread, NULL, print_odd, (void*)nums);

//pthread_join(avgThread, NULL);
//printf("average = %d \n",average);
pthread_join(even_thread, NULL);
pthread_join(odd_thread, NULL);
pthread_mutex_destroy(&count_mutex);
pthread_cond_destroy(&even);
pthread_cond_destroy(&odd);
free(nums);

return 0;

}



void *calcAvg(void *arg)
{
int *val_p = (int *) arg;
int sum = 0;
int i = 0;
for( i = 0; i < size; i++){
sum += val_p[i];
}
average = sum / (size);
pthread_exit(0);
}


// Print even numbers
void *print_even(void *arg)
{
int *arr_p = (int *)arg;
while(count < size)
{
// Lock mutex and then wait for signal to relase mutex
pthread_mutex_lock( &count_mutex );
//Keep looping till the condition becomes even
while( arr_p[count] % 2 == 1 )
pthread_cond_wait( &even, &count_mutex );
printf("Array value print_even: %d\n",arr_p[count]);
count++;
pthread_cond_signal( &odd );
pthread_mutex_unlock(&count_mutex);
}
pthread_exit(0);
}



// print odd numbers
void *print_odd(void *arg)
{
int *arr_p = (int*)arg;
while(count < size)
{
// Lock mutex and then wait for signal to relase mutex
pthread_mutex_lock( &count_mutex );
//Keep looping till the condition becomes odd
while( arr_p[count] % 2 == 0 )
pthread_cond_wait( &odd, &count_mutex );
printf("Array Value print_odd: %d\n", arr_p[count]);
count++;
pthread_cond_signal(&even);
pthread_mutex_unlock(&count_mutex);
}
pthread_exit(0);
}

- anaghakr89 April 19, 2018 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

import java.util.Scanner;

class odd extends Thread
{
    int[] number;
    odd(int[] num){
       this.number = num;
    }
    @Override
    public void run(){
        System.out.println("Odd numbers are:");
        for (int i=0;i<number.length;i++)
        {
            if (number[i]%2!=0)
            {
                System.out.println(i);
            }
        }
    }
}

class even extends Thread{
    int[] number;
    even(int[] num){
       this.number = num;
    }
    @Override
    public void run()
    {
        System.out.println("Even Numbers are");
        for (int i=0; i<number.length; i++)
        {
            if (number[i]%2==0)
            {
                System.out.println(i);
            }
        }
     }

 }


public class EvenOdNumberThread { 
        public static void main(String[] args) throws InterruptedException
        {
            int[] arr = {0,1,2,3,4,5,6,7,8,9,10};

            odd odd1=new odd(arr);
            even even1=new even(arr);

            odd1.start();

            Thread.sleep(5000);
            even1.start();

        }
}

Odd numbers are:
1
3
5
7
9
Even Numbers are
0
2
4
6
8
10

- silvimasss April 19, 2018 | Flag Reply


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