Amazon Interview Question for SDE-3s


Country: India
Interview Type: In-Person




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of 0 vote

boolean isBloodRelated(int id1, int d2){
	if(id1 == id2) return true;
	HashSet<Integer> idSet = new HashSet<>();
	Deque<Integer> queue = new ArrayDeque<>();
	idSet.add(id1);
	idSet.add(id2);
	queue.add(id1);
	queue.add(id2);
	while(!queue.isEmpty()){
		int id = queue.poll();
		Card card = getCard(id);
		int momId = card.getMomId();
		int dadId = card.getDadId();
		if(idSet.contains(momId) || idSet.contains(dadId))return true;
		if(momId != -1){
			queue.add(momId);
			idSet.add(momId);
		}
		if(dadId != -1){
			queue.add(dadId);
			idSet.add(dadId);
		}
	}
	return false;
	}

- Raminder August 03, 2019 | Flag Reply
Comment hidden because of low score. Click to expand.
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of 0 vote

Most important thing is data's organization. Because card objects are billions. But I assumed CardManager class already made this system.

bool isBloodRelated(std::string& id1, std::string& id2) {
    if (id1 == id2) {
        return true;
    }

    JsonObject id1Card;
    if (!CardManager::getCard(id1, id1Card)) {
        throw invalid_argument("Invalid PersonalId: " + id1);
    }

    JsonObject id2Card;
    if (!CardManager::getCard(id1, id2Card)) {
        throw invalid_argument("Invalid PersonalId: " + id2);
    }

    std::set<std::string> blooadRelatedKeys = CardManager::getBloodRelatedKeys();
    if (isMember(id1Card, blooadRelatedKeys)) {
        return true;
    }

    if (isMember(id2Card, blooadRelatedKeys)) {
        return true;
    }

    return false;
}

bool isMember(JsonObject& card, std::set<std::string>& checkingKeys) {
    bool isMember = false;

    std::set<std::string>::iterator iter;
    for (iter = checkingKeys.begin(); iter != checkingKeys.end(); ++iter) {
        std::string& familyId = card.get(*iter);
        if (familyId == id) {
            isMember = true;
            break;
        }
    }

    return isMember;
}

- falloutvoy August 10, 2019 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

Assuming cards is a collection of all the objects

void isBloodRelated(String id1, String id2){
        Map<String, Card> cardId2Obj =  cards.parallelStream().collect( Collectors.toMap( card-> card.myId, card-> card ));
        Card card1 = cardId2Obj.get( id1 );
        Card card2 = cardId2Obj.get( id2 );
        boolean relation = false;
        if(card1.myId.equals( card2.myId )){
            relation = true;
        }else if(card1.momId.equals( card2.myId ) || card1.myId.equals( card2.momId )){
            relation = true;
        }else if(card1.dadId.equals( card2.myId ) || card1.myId.equals( card2.dadId )){
            relation = true;
        }else if(card1.dadId.equals( card2.dadId ) || card1.momId.equals( card2.momId )){
            relation = true;
        }
        else{
            relation = false;
        }

    }

- Chaitanya Kumar August 27, 2019 | Flag Reply


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