Amazon Interview Question for SDE-2s


Team: Payments
Country: United States
Interview Type: In-Person




Comment hidden because of low score. Click to expand.
6
of 6 vote

public class Main {

	public static void main(String[] args) {
		String s1 = "abc";
		String s2 = "de";
		printInterleave(s1,s2);
	}
	
	public static void printInterleave(String s1,String s2){
		String soFar = "";
		printInterleaveUtil(s1,s2,0,0, soFar);
	}
	
	public static void printInterleaveUtil(String s1, String s2, int l1, int l2, String soFar){
		if(l1 == s1.length() && l2 == s2.length()){
			System.out.println(soFar);
			return;
		}
		if(l1 < s1.length()){
			printInterleaveUtil(s1,s2,l1+1,l2,soFar+s1.charAt(l1));
		}
		if(l2 < s2.length()){
			printInterleaveUtil(s1,s2,l1,l2+1,soFar+s2.charAt(l2));
		}
	}
}

- Rakshith Kunchum July 26, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
1
of 1 vote

#include <iostream>
#include <cstring>
using namespace std;
void printPermutations(string str1,string str2,int start1,int start2,string temp)
{
	if (start1==str1.length() && start2==str2.length())
	{
		cout<<temp<<endl;
		return;
	}

	if(start1 < str1.length())
	{	
		printPermutations(str1,str2,start1+1,start2,temp+str1[start1]);
	}	

	if(start2 < str2.length())
	{	
		printPermutations(str1,str2,start1,start2+1,temp+str2[start2]);
	}			

}
int main()
{
	string str1="abc",str2="de";
	string temp="";
	printPermutations(str1,str2,0,0,temp);
	return 0;

}

- tanvi July 26, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
1
of 1 vote

public class Main {

	public static void main(String[] args) {
		String s1 = "abc";
		String s2 = "de";
		printInterleave(s1,s2);
	}
	
	public static void printInterleave(String s1,String s2){
		String soFar = "";
		printInterleaveUtil(s1,s2,0,0, soFar);
	}
	
	public static void printInterleaveUtil(String s1, String s2, int l1, int l2, String soFar){
		if(l1 == s1.length() && l2 == s2.length()){
			System.out.println(soFar);
			return;
		}
		if(l1 < s1.length()){
			printInterleaveUtil(s1,s2,l1+1,l2,soFar+s1.charAt(l1));
		}
		if(l2 < s2.length()){
			printInterleaveUtil(s1,s2,l1,l2+1,soFar+s2.charAt(l2));
		}
	}
}

- Anonymous July 26, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
1
of 1 vote

public class Main {

	public static void main(String[] args) {
		String s1 = "abc";
		String s2 = "de";
		printInterleave(s1,s2);
	}
	
	public static void printInterleave(String s1,String s2){
		String soFar = "";
		printInterleaveUtil(s1,s2,0,0, soFar);
	}
	
	public static void printInterleaveUtil(String s1, String s2, int l1, int l2, String soFar){
		if(l1 == s1.length() && l2 == s2.length()){
			System.out.println(soFar);
			return;
		}
		if(l1 < s1.length()){
			printInterleaveUtil(s1,s2,l1+1,l2,soFar+s1.charAt(l1));
		}
		if(l2 < s2.length()){
			printInterleaveUtil(s1,s2,l1,l2+1,soFar+s2.charAt(l2));
		}
	}
}

- settyblue July 26, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

<?php
$data = "abc"."de";
$abc = str_shuffle($data);
echo $abc;
?>

- rahul kumar July 26, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

public class StringInterleaving {

public static void main(String argsp[]) {
String s1="abc",s2="de";
printInterleaving(s1, s2, 0);
printInterleaving(s2, s1, 0);
}

public static void printInterleaving(String s1, String s2, int index) {
System.out.println(s1.substring(0, index)+s2+s1.substring(index));
if(index+1 <= s1.length()) {
printInterleaving(s1, s2, index+1);
}
}
}

- Raja July 26, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

{{public class StringInterleaving {

public static void main(String argsp[]) {
String s1="abc",s2="de";
printInterleaving(s1, s2, 0);
printInterleaving(s2, s1, 0);
}

public static void printInterleaving(String s1, String s2, int index) {
System.out.println(s1.substring(0, index)+s2+s1.substring(index));
if(index+1 <= s1.length()) {
printInterleaving(s1, s2, index+1);
}
}
}
}}

- Raja July 26, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

def il(s1,s2,prefix=''):
    if len(s2) == 0 or len(s1) == 0:
        yield prefix+s1+s2
    else:
        yield from il(s1[1:], s2, prefix+s1[0])
        yield from il(s1, s2[1:], prefix+s2[0])

print(list(il('abc','de')))

- Edward July 27, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

def il(s1,s2,prefix=''):
    if len(s2) == 0 or len(s1) == 0:
        yield prefix+s1+s2
    else:
        yield from il(s1[1:], s2, prefix+s1[0])
        yield from il(s1, s2[1:], prefix+s2[0])

print(list(il('abc','de')))

- Edward July 27, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

{{public void interleave(String first, String second) {
for (int i = 0; i < first.length(); i++) {
for (int j = 0; j < second.length(); j++) {
System.out.println(first.substring(0, i + 1) + second.substring(0, j + 1) + first.substring(i + 1)
+ second.substring(j + 1));
}
}
}}}

- Vicky Maniyar July 29, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

/*
 * InterLeavingStrs.cpp
 *
 *  Created on: Jul 29, 2016
 *      Author: chandra.shekhar
 */
#include<iostream>
#include<stdio.h>
#include<string.h>

using namespace std;

#define BUFF 25

void InterLeaveStrs(char *s1, char *s2, int n, int m, char *dest, int destIdx){

	if(n == strlen(s1) && m == strlen(s2) ){
		cout << "String is " << dest << endl ;
		return;
	}
	if(n < strlen(s1)){
		dest[destIdx] = s1[n];
		InterLeaveStrs(s1,s2,n+1, m,dest, destIdx+1);
	}
	if(m < strlen(s2)){
		dest[destIdx] = s2[m];
		InterLeaveStrs(s1,s2,n, m+1,dest, destIdx+1);
	}

}
int main(){

	char s1[BUFF];
	char s2[BUFF];

	cout << endl <<  "Enter String 1 " << endl ;
	cin >> s1;
	cout << "Enter String 2" << endl;
	cin >> s2;
	char dest[BUFF];
	memset(dest, '\0', BUFF);
	InterLeaveStrs(s1,s2,0,0,dest,0);



	return 0;
}

- Anonymous July 29, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

public static void main(String[] args) {
test t = new test();

DP dp = new DP();
dp.merge("abcd","ef");

}

public void merge(String s1 , String s2){

compute(s1,s2,"", new ArrayList<>());

}

private void compute(String s1, String s2, String res , List<String>resList) {
if(s1.length() == 0)
{
System.out.println(res+s2);
}

else if(s2.length() ==0){
System.out.println(res+s1);

}

else{

compute(s1.substring(1),s2,res+s1.charAt(0),resList) ;
compute(s1,s2.substring(1),res+s2.charAt(0),resList) ;

}
}

- Satya August 02, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

public void merge(String s1 , String s2){

        compute(s1,s2,"", new ArrayList<>());

    }

    private void compute(String s1, String s2, String res , List<String>resList) {
       if(s1.length() == 0)
       {
           System.out.println(res+s2);
       }

      else if(s2.length() ==0){
           System.out.println(res+s1);

       }

       else{

           compute(s1.substring(1),s2,res+s1.charAt(0),resList) ;
           compute(s1,s2.substring(1),res+s2.charAt(0),resList) ;

       }
    }

- Satya August 02, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

public void merge(String s1 , String s2){

        compute(s1,s2,"", new ArrayList<>());

    }

    private void compute(String s1, String s2, String res , List<String>resList) {
       if(s1.length() == 0)
       {
           System.out.println(res+s2);
       }

      else if(s2.length() ==0){
           System.out.println(res+s1);

       }

       else{

           compute(s1.substring(1),s2,res+s1.charAt(0),resList) ;
           compute(s1,s2.substring(1),res+s2.charAt(0),resList) ;

       }
    }

- Satya August 02, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

if you're just interleaving, isn't it basically a DFS where you walk down the two strings?

function weaveStrings(stringSoFar, firstString, secondstring){
    if(firstString === "" && secondString === ""){
        console.log(stringSoFar);
    } else {
        if(firstString.length > 0){
            weaveStrings(stringSoFar + firstString.charAt(0), firstString.subString(1), secondString);
        } 
        if(secondString.length > 0){
            weaveStrings(stringSoFar + secondString.charAt(0), firstString, secondString.subString(1))
        }    
    }
}

function printInterweavings(firstString, secondString){
    if(firstString === null || typeof(firstString) === "undefined"){
        throw {
            name: "argumentException",
            message: "first string is null or undefined"
        }
    }
    if(secondString === null || typeof(secondString) === "undefined"){
        throw {
            name: "argumentException",
            message: "second string is null or undefined"
        }
    }
    if(firstString.length > 0 || secondString.length > 0){       
        weaveStrings("", firstString, secondString);
    }
}

- Anonymouse August 04, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

public static void main(String[] args) {

printComb("ab","def",0,0,"");
}

public static void printComb(String s1,String s2,int i1,int i2, String soFar ){

if((s1 == null || s1.length() == i1) && (s2 == null || s2.length() == i2)){
System.out.println(soFar);
}
if(s1.length() > i1){
printComb(s1, s2, i1+1, i2, soFar+s1.charAt(i1));
}
if(s2.length() > i2){
printComb(s1, s2, i1, i2+1, soFar+s2.charAt(i2));

}
}

- MVVSK August 20, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

def rec(a,b,sofar=""):
	if len(a)==0 and len(b)==0:
		print(sofar)
		return
	if len(a)==0:
		rec([],[], sofar + b)
	elif len(b)==0:
		rec([],[], sofar + a)
	else:
		rec(a[1:], b, sofar + a[0])
		rec(a, b[1:], sofar + b[0])

- Anonymous February 06, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

def rec(a,b,sofar=""):
	if len(a)==0 and len(b)==0:
		print(sofar)
		return
	if len(a)==0:
		rec([],[], sofar + b)
	elif len(b)==0:
		rec([],[], sofar + a)
	else:
		rec(a[1:], b, sofar + a[0])
		rec(a, b[1:], sofar + b[0])

- A February 06, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
-1
of 1 vote

public static void main(String args[])
	{
		String s1="abc",s2="de";
				
		print_inter_leave(s1,s2,0);
	}

	private static void print_inter_leave(String s1, String s2,int index) {
	
		if(s2.length()==0)
			return;
		
		for(int i=0;i<=s1.length()-index;i++)
		{
			System.out.println(s1.substring(0, i+index)+s2+s1.substring(i+index));
    								print_inter_leave(s1.substring(0,i+index)+s2.substring(0,1)+s1.substring(i+index),s2.substring(1),i+2);
		}
		
	}

- Ashish Singh July 26, 2016 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

This code does not work. Please try with "abc" and "def" to see that.

- deepdawg July 27, 2016 | Flag


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