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x=x++ + ++y; 
y=y++ + ++x;

Both these statements shows undefined behavior. Study about sequence points in C or C++. Between the previous and next sequence point, a scalar object shall have its stored value modified at most once by the evaluation of an expression.

#include<iostream>
using namespace std;
int main()
{ int x,y;
x=10,y=20;
x=x++ + ++y;
y=y++ + ++x;
cout<<"x is "<<x<<endl;
cout<<"y is " <<y;
return 0;

#include<iostream>
using namespace std;
int main()
{ int x,y;
x=10,y=20;
x=x++ + ++y;
y=y++ + ++x;
cout<<"x is "<<x<<endl;
cout<<"y is " <<y;
return 0;
}

#include<iostream>
using namespace std;
int main()
{ int x,y;
x=10,y=20;
x=x++ + ++y;
y=y++ + ++x;
cout<<"x is "<<x<<endl;
cout<<"y is " <<y;
return 0;

}

x=31,y=53
x=10+21
y=21+32

int x=10 ,y=20;
x=x++ + ++y;
y=y++ + ++x;
cout<<x<<" "<<y; // output: 32 53

thnx a lot guys..

which language? In c++ thats undefined I believe

rply me fast ...m wiating..