Collective Interview Question for Software Engineer / Developers


Country: India
Interview Type: In-Person




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of 0 vote

public class Main {
	
	public static void main ( String [] arguments )
    {
    
		int [] digits = new int[6];
		int count = checkNextDigits(digits, 0, 0);
		System.out.println("Found " + count + " numbers");
		
    }
	
	
	public static int checkNextDigits(int [] progress, int N, int count) {
		
		if (N == 6) {
			 
			String number = "";
			
			for (int i = 0; i < 6; i ++) {
			
				number += progress[i] + ((i < 5) ? "-" : "");
				
			}
			
			System.out.println(number);
			return count + 1;
			
		}
		
		
		for (int i = 0; i <= 9; i ++) {
				
			if (N == 0) {

				if (i > 0) {
				
					progress[0] = i;
					count = checkNextDigits(progress, 1, count);
						
				}
				
			} else {
				
				int pv = progress[N - 1] == 0 ? 10 : progress[N - 1] - 1;
				int cv = i == 0 ? 10 : i - 1;
				
				if (pv == cv) 
					continue;
				
				int rp = pv % 3;
				int dp = pv / 3;
				int rc = cv % 3;
				int dc = cv / 3;
				
				if (rp == rc || dp == dc) {
					
					boolean occurs = false;
					
					for (int j = 0; j < N + 1; j ++) {
					
						if (progress[j] == i)
							occurs = true;
						
					}
					
					if (!occurs) {
						
						progress[N] = i;
						count = checkNextDigits(progress, N + 1, count);
							
					}
						
				}
		
			}
		
		}

		return count;
			
	}
	
}

- Joris Weimar April 29, 2014 | Flag Reply
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of 0 vote

Found 2074 numbers total

public class Main {
	
	public static void main ( String [] arguments )
    {
    
		int [] digits = new int[6];
		int count = checkNextDigits(digits, 0, 0);
		System.out.println("Found " + count + " numbers");
		
    }
	
	
	public static int checkNextDigits(int [] progress, int N, int count) {
		
		if (N == 6) {
			 
			String number = "";
			
			for (int i = 0; i < 6; i ++) {
			
				number += progress[i] + ((i < 5) ? "-" : "");
				
			}
			
			System.out.println(number);
			return count + 1;
			
		}
		
		
		for (int i = 0; i <= 9; i ++) {
				
			if (N == 0) {

				if (i > 0) {
				
					progress[0] = i;
					count = checkNextDigits(progress, 1, count);
						
				}
				
			} else {
				
				int pv = progress[N - 1] == 0 ? 10 : progress[N - 1] - 1;
				int cv = i == 0 ? 10 : i - 1;
				
				if (pv == cv) 
					continue;
				
				int rp = pv % 3;
				int dp = pv / 3;
				int rc = cv % 3;
				int dc = cv / 3;
				
				if (rp == rc || dp == dc) {
					
					boolean occurs = false;
					
					for (int j = 0; j < N + 1; j ++) {
					
						if (progress[j] == i)
							occurs = true;
						
					}
					
					if (!occurs) {
						
						progress[N] = i;
						count = checkNextDigits(progress, N + 1, count);
							
					}
						
				}
		
			}
		
		}

		return count;
			
	}
	
}

- jbweimar April 29, 2014 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

in this what is the use case... i mean if my number is 5,

Then what numbers should be the output?

- jassi.srmcem May 02, 2014 | Flag Reply


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