Uber Interview Question for Software Engineers


Country: United States




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1
of 1 vote

This could be solved using minimum spanning tree concept

***assume taxi is large enough for all passengers****

Arrange all the pickup locations as vertices of a graph along with the present location of the taxi as

one of the vertex

now start with the present location and add that edge with has lowest weight ,this means we have

visited to the location which is nearby and pic all the passangers, then search for the next nearby location

locations and so on until all the locations are visited once

- Harsh Bhardwaj February 17, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

I should add this to the problem: driver just pick up one person for each location.

- sonya.abdoli February 17, 2017 | Flag Reply
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0
of 0 vote

Isn't it traveling salesman problem?

- afroza.sultana.kakon March 13, 2017 | Flag Reply
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0
of 0 vote

hmm... do you mean all permutations like
person1 - person6 - person 10 - person 13
person1 - person7 - person 10 - person 13
person1 - person8 - 10 - 13
1 - 9 - 10 - 13
1 - 6 - 11 - 13
etc...

- ChrisK March 13, 2017 | Flag Reply
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0
of 0 vote

If the question is to get all permutations then this should do the trick:

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

/**
 * Created by dirkhain on 4/10/17.
 */
public class UberPickup {

    public static void main (String[] args) {
        UberPickup u = new UberPickup();
        List<String[]> input = new ArrayList<>();
        input.add(new String[]{"P1", "P2", "P3"});
        input.add(new String[]{"P4", "P5", "P6"});
        input.add(new String[]{"P7", "P8"});
        List<String> result = u.getPermutations(input);
        for (String s : result) {
            System.out.println(s);
        }
    }

    public List<String> getPermutations(List<String[]> input) {
        ArrayList<String> result = new ArrayList<>();
        if(input.size() == 0) {
            return Arrays.asList("");
        }
        String[] current = input.get(0);
        //copy rest of array
        List<String[]> rest = input.subList(1, input.size());
        List<String> subCombos = getPermutations(rest);
        for(String s : current) {
            for(int i = 0; i < subCombos.size(); i++) {
                String combo = subCombos.get(i);
                result.add("->" + s + combo);
            }
        }
        return result;
    }
}

If the question is not about retrieving the permutations then this solution will not work.

- dhc April 10, 2017 | Flag Reply


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