Google Interview Question for Software Engineers


Country: United States
Interview Type: In-Person




Comment hidden because of low score. Click to expand.
1
of 1 vote

Hi Fernando,

I interpret the problem this way - making someone my colleague means having him into my team (assigning my manager to him). Since it is a design problem it's open-ended and your solution would be good as well.

Thanks for the reply!

- aonecoding August 06, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 2 vote

class Employee {

    int id;
    private String name;
    //...other personal information
    private Employee manager;
    private List<Employee> subordinates; //direct subordinates

    public Employee(int id, String name) {
        this.id = id;
        this.name = name;
        subordinates = new ArrayList<>();
    }

    boolean isManager(Employee manager) {
        Employee upperLevel = this.manager;
        while(upperLevel != null && upperLevel != manager) {
            upperLevel = upperLevel.manager;
        }
        return upperLevel.manager == manager;
    }

    void beColleague(Employee p) {
        p.setManager(this.manager);
    }

    void setManager(Employee m) {
        if(manager != null) {   //remove from subordinate's list of current manager
            manager.deleteSubordinate(this);
        }
        manager = m;
        m.addSubordinate(this); //add to new manager's subordinate's list
    }

    private void deleteSubordinate(Employee m) {
        subordinates.remove(m);
    }

    private void addSubordinate(Employee m) {
        subordinates.add(m);
    }

}

public class Employment {

    private Employee admin;
    private Map<Integer, Employee> employees;               //id: employee

    public Employment() {
        admin = new Employee(0, "ADMINISTRATOR");  //root of the employment tree, the highest level supervisor
        employees = new HashMap<>();
        employees.put(0, admin);
    }

    public void assignManager(int p1, int p2) {
        employees.get(p2).setManager(employees.get(p1));
    }

    public void beColleague(int p1, int p2) {
        employees.get(p2).beColleague(employees.get(p1));
    }

    public boolean isManager(int p1, int p2) {
        return employees.get(p2).isManager(employees.get(p1));
    }

    //public void addEmployee(int p);
    //public void deleteEmployee(int p);

}

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- aonecoding August 03, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

Hello!!! I have been reading the code and I am confused with the function

void beColleague(Employee p);

Why is it basically a renaming of setManager?? Shouldn't be something like

void beColleague(Employee p) {
	if (manager == p) { // p is our manager
		manager = p.manager;
		p.deleteSubordinate(this);
	}
	else if (p.manager == this) { // we are the manager of p
		p.manager = manager;
		deleteSubordinate(p);
	}
}

Cheers :)

- Fernando August 03, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

mlkmlk
m;l

- Anonymous August 21, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

I assume that a manager can have their manager too, and that the hierarchy is acyclic (i.e. you can't be a manager of an upper of yours).

class Employee {
	public:
		Employee(int id)
		{
			id_ = id;
			manager_ = NULL;
		}
		Employee *manager_;
		unordered_set<Employee *> subordinates_;
		int id_;
};

class Employment {
	public:
		void AssignManager(Employee *manager, Employee *subordinate)
		{
			if (manager &&
				subordinate)
			{
				if (subordinate->manager_) {
					subordinate->manager_->subordinates_.erase(subordinate);
				}
				subordinate->manager_ = manager;
				subordinate->manager_->subordinates_.insert(subordinate);
			}
		}
		void BeColleagues(Employee *e1, Employee *e2)
		{
			if (e1 &&
				e2 &&
				e1->manager_ != e2->manager_)
			{
				if (e1->manager_ == NULL) {
					AssignManager(e2->manager_, e1);
				} else if (e2->manager_ == NULL) {
					AssignManager(e1->manager_, e2);
				} else {
					if (HierarchyLevel(e1) < HierarchyLevel(e2)) {
						AssignManager(e1->manager_, e2);
					} else {
						AssignManager(e2->manager_, e1);
					}
				}
			}
		}
		bool IsManager(Employee const *manager, Employee const *subordinate) const
		{
			if (manager &&
				subordinate)
			{
				for (Employee const *upper = subordinate->manager_; upper != NULL; upper = upper->manager_) {
					if (upper == manager) {
						return true;
					}
				}
			}
			return false;
		}

	private:
		int HierarchyLevel(Employee const *e) const
		{
			int level = 0;
			if (e) {
				for (Employee const *upper = e->manager_; upper != NULL; upper = upper->manager_) {
					++level;
				}
			}
			return level;
		}
};

- Alex September 01, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

IMO, this question seems to be asking the union-find algorithm, which allows us to identify disjoint-set relationship.

- sec October 10, 2017 | Flag Reply


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