Google Interview Question for Software Engineers

Country: United States
Interview Type: In-Person

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of 4 vote

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import java.util.List;
import java.util.ArrayList;

public class IntegerCollection {
    List<Integer> collection = new ArrayList<>();
    List<Integer> divisors = new ArrayList<>();
    int factor = 1;
    int addition = 0;
    int set0 = -1;

    public void append(int x) {
        collection.add(x - addition);

    public int get(int index) {
        if(index >= collection.size()) throw new RuntimeException();
        if(divisors.get(index) <= set0) return addition;
        return collection.get(index) * (factor / divisors.get(index)) + addition;

    public void add_to_all(int x) {
        addition += x;

    public void multiply_to_all(int x) {
        if(x == 0) {
            addition = 0;
            factor = 1;
            set0 = collection.size() - 1;
        } else {
            addition *= x;
            factor *= x;

- aonecoding September 22, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
of 2 vote

The best approach is to keep track of the operations and apply the reverse operation when you insert the number. In this way the insertion keeps track of the previous operations.

class IntegerCollection
	List<double> N = new List<double>();
	double mult = 1, sum = 0;
        int zeroIndex = -1;

	public void insert(int x) 
		N.Add(x/mult - sum);

	public void sum_to_all(int x)
		sum+= x;

	public void multiply_to_all(int x)
                if(x ==0) {
                    zeroIndex = N.Length -1;
                    mult = 1;
                    sum = 0;
                else {
		    sum *= x;
		    mult *= x;

	public int get(int x)
                if (x <= zeroIndex) return sum;

		return (int) (N[x]*mult + sum);

- Nelson Perez October 09, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
of 1 vote

@aonecoding Very nice. But don't you mean "index <= set0" rather than "divisors.get(index) <= set0" in line 18?

- Shahar October 06, 2017 | Flag Reply
Comment hidden because of low score. Click to expand.
of 0 vote

It doesn't seem the solutions here work for the case in which addition comes before multiplication like in the input sample, do they? Also, I couldn't figure out how to implement "get()" in O(1) if we keep switching the order of add_to_all and multiply_to_all, like in the input sample below:

get(0) -> returns 6
get(2) -> return 3
get(1) -> returns 70
get(2) -> returns 30
get(3) -> returns 4

Adding the following lines:
get(0) →364

get(0) -> 1820

- fernandoVieiraDaSilva October 09, 2017 | Flag Reply

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