CareerCup

actually hex A is different from character 'A'.
0xA = 10 = '\n'
'A' = 41 = 0x29

I did not follow the question - is this equivalent to converting hexadecimal given as a string into a decimal integer ?

If I understand correctly, the question is:
If you have to print the character out in ASCII format, what should you ask yourself first?

That question should be: Is the given string (that is in Hex) is already encoded in ASCII or not?
If each character uses 1 byte, it is very likely that it is already in ASCII.

Hey isara..

damn true what u said...goood one..!!

Hexadecimal has characters are from 0-9 and A-F. all these characters can be represented in 1 byte. So all hexadecimal numbers are already in ascii format.

Is there anything wrong here?

I see whats going on with this question- I looked up the meaning of ASCII- its an encoding format that uses 7 bits - it can be represented by binary, decimal, hexadecimal etc. So if we are given a hex string, then as isara hinted, the question would be what is the input format ? I guess that depends on the Hardware/system that is used to feed the input!

Initially I got the impression that what was being asked was something like atoi().

but hex numbers take 4 bits while unsigned ascii takes 8 bits

//code
while(*str)
{
printf("%c", (*str<<4)|*(str+1));
str++;
if(str)
str++;
else break;
}

Ex: AE0F912EA
then AE 0F 91 2E and A are ascii characters

Isn't Hex A = dec 10 = ascii '\n'?
ascii 'A' is Hex 41?
Please can u explain?