Interview Question


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0
of 0 vote

Here .
[ geeksforgeeks.org/search-an-element-in-a-sorted-and-pivoted-array/ ]

- NoOne June 13, 2019 | Flag Reply
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0
of 0 vote

This is my solution -

class SortedArrayElementPivot {

  static int search(int[] array, int elementToSearch) {
    if (array == null || array.length == 0) {
      return -1;
    }

    return search(array, elementToSearch, 0, array.length - 1);
  }

  private static int search(int[] array, int elementToSearch, int start, int end) {
    if (array == null || array.length == 0 || start < 0 || start > end || end > array.length - 1) {
      return -1;
    }

    int mid = (start + end) / 2;
    if (array[mid] == elementToSearch) {
      return mid;
    }

    if (
      // mid is pivot
        (mid > 0 && array[mid - 1] > array[mid])

            // next to mid is pivot
            || (mid + 1 <= end) && array[mid] > array[mid + 1]) {

      int leftSearchResult = binarySearch(array, elementToSearch, start, mid - 1);
      return leftSearchResult != -1 ? leftSearchResult : binarySearch(array, elementToSearch, mid + 1, end);
    } else {
      int leftSearchResult = search(array, elementToSearch, start, mid - 1);
      return leftSearchResult != -1 ? leftSearchResult : search(array, elementToSearch, mid + 1, end);
    }
  }

  private static int binarySearch(int[] array, int elementToSearch, int start, int end) {
    if (array == null || array.length == 0 || start < 0 || start > end || end > array.length - 1) {
      return -1;
    }
    int mid = (start + end) / 2;
    if (array[mid] == elementToSearch) {
      return mid;
    } else if (array[mid] < elementToSearch) {
      return binarySearch(array, elementToSearch, mid + 1, end);
    } else {
      return binarySearch(array, elementToSearch, start, mid - 1);
    }
  }
}

- learning-algorithms June 14, 2019 | Flag Reply


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