Google Interview Question


Country: Germany
Interview Type: Phone Interview




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0
of 0 vote

{
l=[] #l[y][x]
#_________0123456789
l.append('100000000')
l.append('110111111')
l.append('111110001')
l.append('000111011')

sx,sy=-1,-1
ex,ey=-1,-1
c=-1

def pix(x,y): #-1 if out of image
if x<0 or x>=len(l[0]) or y<0 or y>=len(l):
return -1
return int(l[y][x])

def isStart(x,y):
cc=pix(x,y)
if cc!=pix(x-1,y-1) and cc!=pix(x,y-1) and cc!=pix(x+1,y-1) and cc!=pix(x-1,y) and cc==pix(x+1,y) and cc!=pix(x-1,y+1) and cc!=pix(x,y+1)and cc!=pix(x+1,y+1):
return cc
return -1

def isEnd(x,y):
cc=pix(x,y)
if cc!=pix(x-1,y-1) and cc!=pix(x,y-1) and cc!=pix(x+1,y-1) and cc==pix(x-1,y) and cc!=pix(x+1,y) and cc!=pix(x-1,y+1) and cc!=pix(x,y+1) and cc!=pix(x+1,y+1):
return cc
return -1

def isLine(x,y):
cc=pix(x,y)
if cc!=pix(x,y-1) and cc==pix(x-1,y) and cc!=pix(x,y+1):
return cc
return -1

def draw():
for y in range(len(l)):
for x in range(len(l[0])):
cl = pix(x,y)
if y == sy and y == ey and sx<=x and x <= ex:
print("\033[33;1;%d;9m%d\033[m" %(40+7*cl,cl), end='')
else:
print("\033[33;%dm%d\033[m" %(40+7*cl,cl), end='')
print()

draw()

for i in range(len(l)*len(l[0])):
x = i % len(l[0])
y = int(i / len(l[0]))
cs = isStart(x,y)
cl = isLine(x,y)
ce = isEnd(x,y)

if c>=0:
if ce>=0:
ex,ey=x,y
print("\033[42mFOUN x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d \033[7msx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
break
elif cl>=0: #continue
print("\033[46mCONT x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
elif cs<0: #broken no new line
c,sx,sy,ex,ey=cs,-1,-1,-1,-1
print("\033[41mFAIL x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
else: #restart new line
c,sx,sy,ex,ey=cs,x,y,x,y
print("\033[43mRETR x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
elif cs>=0:
c,sx,sy,ex,ey=cs,x,y,x,y
print("\033[44mSTAR x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
else:
print("NONE x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))

draw()
}

- MR February 29, 2020 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

l=[] #l[y][x]
#_________0123456789
l.append('100000000')
l.append('110111111')
l.append('111110001')
l.append('000111011')

sx,sy=-1,-1
ex,ey=-1,-1
c=-1

def pix(x,y): #-1 if out of image
    if x<0 or x>=len(l[0]) or y<0 or y>=len(l):
        return -1
    return int(l[y][x])

def isStart(x,y):
    cc=pix(x,y)
    if cc!=pix(x-1,y-1) and cc!=pix(x,y-1) and cc!=pix(x+1,y-1) and cc!=pix(x-1,y) and cc==pix(x+1,y) and cc!=pix(x-1,y+1) and cc!=pix(x,y+1)and cc!=pix(x+1,y+1):
        return cc
    return -1

def isEnd(x,y):
    cc=pix(x,y)
    if cc!=pix(x-1,y-1) and cc!=pix(x,y-1) and cc!=pix(x+1,y-1) and cc==pix(x-1,y) and cc!=pix(x+1,y) and cc!=pix(x-1,y+1) and cc!=pix(x,y+1) and cc!=pix(x+1,y+1):
        return cc
    return -1

def isLine(x,y):
    cc=pix(x,y)
    if cc!=pix(x,y-1) and cc==pix(x-1,y) and cc!=pix(x,y+1):
        return cc
    return -1

def draw():    
    for y in range(len(l)):
        for x in range(len(l[0])):
            cl = pix(x,y)
            if y == sy and y == ey and sx<=x and x <= ex:                
                print("\033[33;1;%d;9m%d\033[m" %(40+7*cl,cl), end='')
            else:
                print("\033[33;%dm%d\033[m" %(40+7*cl,cl), end='')            
        print()

draw()

for i in range(len(l)*len(l[0])):
        x = i % len(l[0])
        y = int(i / len(l[0]))
        cs = isStart(x,y)
        cl = isLine(x,y)
        ce = isEnd(x,y)

        if c>=0:
            if ce>=0:
                ex,ey=x,y
                print("\033[42mFOUN x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d \033[7msx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
                break
            elif cl>=0: #continue
                print("\033[46mCONT x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
            elif cs<0: #broken no new line
                c,sx,sy,ex,ey=cs,-1,-1,-1,-1
                print("\033[41mFAIL x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
            else: #restart new line
                c,sx,sy,ex,ey=cs,x,y,x,y
                print("\033[43mRETR x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
        elif cs>=0: 
            c,sx,sy,ex,ey=cs,x,y,x,y
            print("\033[44mSTAR x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
        else:
            print("NONE x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))

draw()

- Anonymous February 29, 2020 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

l=[] #l[y][x]
l.append('100000000')
l.append('110111111')
l.append('111110001')
l.append('000111011')

sx,sy=-1,-1
ex,ey=-1,-1
c=-1

def pix(x,y): #-1 if out of image
    if x<0 or x>=len(l[0]) or y<0 or y>=len(l):
        return -1
    return int(l[y][x])

def isStart(x,y):
    cc=pix(x,y)
    if cc!=pix(x-1,y-1) and cc!=pix(x,y-1) and cc!=pix(x+1,y-1) and cc!=pix(x-1,y) and cc==pix(x+1,y) and cc!=pix(x-1,y+1) and cc!=pix(x,y+1)and cc!=pix(x+1,y+1):
        return cc
    return -1

def isEnd(x,y):
    cc=pix(x,y)
    if cc!=pix(x-1,y-1) and cc!=pix(x,y-1) and cc!=pix(x+1,y-1) and cc==pix(x-1,y) and cc!=pix(x+1,y) and cc!=pix(x-1,y+1) and cc!=pix(x,y+1) and cc!=pix(x+1,y+1):
        return cc
    return -1

def isLine(x,y):
    cc=pix(x,y)
    if cc!=pix(x,y-1) and cc==pix(x-1,y) and cc!=pix(x,y+1):
        return cc
    return -1

def draw():    
    for y in range(len(l)):
        for x in range(len(l[0])):
            cl = pix(x,y)
            if y == sy and y == ey and sx<=x and x <= ex:                
                print("\033[33;1;%d;9m%d\033[m" %(40+7*cl,cl), end='')
            else:
                print("\033[33;%dm%d\033[m" %(40+7*cl,cl), end='')            
        print()

draw()

for i in range(len(l)*len(l[0])):
        x = i % len(l[0])
        y = int(i / len(l[0]))
        cs = isStart(x,y)
        cl = isLine(x,y)
        ce = isEnd(x,y)

        if c>=0:
            if ce>=0:
                ex,ey=x,y
                print("\033[42mFOUN x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d \033[7msx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
                break
            elif cl>=0: #continue
                print("\033[46mCONT x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
            elif cs<0: #broken no new line
                c,sx,sy,ex,ey=cs,-1,-1,-1,-1
                print("\033[41mFAIL x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
            else: #restart new line
                c,sx,sy,ex,ey=cs,x,y,x,y
                print("\033[43mRETR x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
        elif cs>=0: 
            c,sx,sy,ex,ey=cs,x,y,x,y
            print("\033[44mSTAR x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))
        else:
            print("NONE x=%2d y=%2d v=%2d cs=%2d cl=%2d ce=%2d c=%2d sx=%2d sy=%2d ex=%2d ey=%2d\033[m" %(x,y,pix(x,y),cs,cl,ce,c,sx,sy,ex,ey))

draw()

- MER February 29, 2020 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

Use sobel kernel or hough tranform

- Anonymous March 23, 2020 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 vote

Use sobel kernel or hough tranform

- Sumit March 23, 2020 | Flag Reply


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