Sabre Holdings Interview Question for Java Developers


Country: India




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LeetCode 202. Happy Number

- Sithis March 19, 2019 | Flag Reply
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something like this should be ok

public static void main(String[] args) {
    var input = new Scanner(System.in);
    System.out.print("Enter number <0 to exit> : ");
    var n = input.nextInt();
    while (n != 0) {
        System.out.println(isHappy(n) ? 1 : 0);
        System.out.print("Enter number <0 to exit> : ");
        n = input.nextInt();
    }
}

private static boolean isHappy(int n) {
    var set = new HashSet<Integer>();
    int computed;
    do {
        computed = 0;
        set.add(n);
        while (n > 0) {
            computed += square(n % 10);
            n /= 10;
        }
        if (set.contains(computed)) break;
        n = computed;
    } while (computed != 1);
    return computed == 1;
}

private static int square(int i) { return i * i; }

- PeyarTheriyaa March 20, 2019 | Flag Reply
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0
of 0 vote

We can massively reduce the code by following this :
[ en.wikipedia.org/wiki/Happy_number ] and following that :

All unhappy numbers follow sequences that eventually reach the eight-number cycle

4 → 16 → 37 → 58 → 89 → 145 → 42 → 20 → 4 → ...

- NoOne March 23, 2019 | Flag Reply
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of 0 vote

class HappyNumber {

static int numSquareSum(int n) {
int squareSum = 0;
while (n!= 0) {
squareSum += (n % 10) * (n % 10);
n /= 10;
}
return squareSum;
}

// method return true if n is Happy number
static boolean isHappynumber(int n) {
int slow, fast;
slow = fast = n;
do {
slow = numSquareSum(slow);
fast = numSquareSum(numSquareSum(fast));
} while (slow != fast);
return (slow == 1);
}

public static void main(String[] args) {
int n = 13;
if (isHappynumber(n))
System.out.println(n + " is a Happy number");
else
System.out.println(n + " is not a Happy number");
}
}

- preety May 08, 2019 | Flag Reply


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