Epic Systems Interview Question for Software Developers


Country: United States




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public static void main(String[] args) {
    String str = "DABC";
    int[] vals = new int[26];
    vals['A'-'A'] = 1;
    vals['B'-'A'] = 13;
    vals['C'-'A'] = 110;
    vals['D'-'A'] = 50;
    
    int n = print(vals, str.toCharArray());
    System.out.println(n);
  }
  
  public static int print(int[] vals, char[] carr){
  
    int n = carr.length -2;
    char next = carr[n+1];
    int sum = vals[next-'A'];
    int mul = 1;
    
    while(n >= 0){
      	//uncomment next line if the sum should be + 50 - 1 - 13 + 110
        // keep commentted if the sum be - 50 - 1 - 13 + 110
        //mul = 1;
      	if(next > carr[n])
          mul = -1;
      	sum += vals[carr[n]-'A']*mul;
    	next = carr[n];
      	n--;
    }
    return sum;
  }

- sudip.innovates October 13, 2017 | Flag Reply
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of 0 vote

import java.util.HashMap;

public class Alphabet {
    public static void main(String[] args) {
        System.out.println(calculateString("ABC"));
        System.out.println(calculateString("CBA"));
    }

    private static int calculateString(String str) {
        HashMap<Character, Integer> map = generateHashMap();
        char[] chars = str.toCharArray();

        int i, sum = 0;
        for (i = 0; i < chars.length - 1; i++) {
            int firstValue = map.get(chars[i]);
            int nextValue = map.get(chars[i + 1]);

            if (firstValue > nextValue) {
                sum += firstValue;
            } else {
                sum -= firstValue;
            }
        }

        sum += map.get(chars[i]);

        return sum;
    }

    private static HashMap<Character, Integer> generateHashMap() {
        HashMap<Character, Integer> characterMap = new HashMap<>();
        characterMap.put('A', 1);
        characterMap.put('B', 13);
        characterMap.put('C', 110);
        return characterMap;
    }

}

- jiangdavid62 November 03, 2018 | Flag Reply
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of 0 vote

dict={'A':1,'B':13,'C':110}
def AlphaAndArabic(s):
individual_letter=list(s)
sum=dict[individual_letter[0]]
for i in range(1,len(s)):
curr=individual_letter[i]
if(i!=len(s)-1):
if(curr>=individual_letter[i-1]):
sum=-sum
sum-=dict[curr]
else:
sum+=dict[curr]
else:
sum+=dict[curr]
return(sum)

AlphaAndArabic("CBA")

- Anonymous February 23, 2022 | Flag Reply
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of 0 vote

dict={'A':1,'B':13,'C':110}
def AlphaAndArabic(s):
    individual_letter=list(s)
    sum=dict[individual_letter[0]]
    for i in range(1,len(s)):
        curr=individual_letter[i]
        if(i!=len(s)-1):
            if(curr>=individual_letter[i-1]):
                sum=-sum
                sum-=dict[curr]
            else:
                sum+=dict[curr]
        else:
            sum+=dict[curr]
    return(sum)

AlphaAndArabic("CBA")

- Anonymous February 23, 2022 | Flag Reply
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0
of 0 vote

C# solution

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace Test
{
    class AlphaAndarabic
    {
        public static Dictionary<string, int> alphabets;

        public static void Main(string[] args) {
            string letters = Console.ReadLine().Trim();
            alphabets = new Dictionary<string, int>();
            alphabets.Add("A", 1);
            alphabets.Add("B", 13);
            alphabets.Add("C", 110);

            int result = alphaAndarabic(letters);

            Console.WriteLine(Convert.ToString(result));
        }

        public static int alphaAndarabic(string pLetters) {
            int nextIdx = 0;
            int total = 0;
            int valueCurrent = 0;
            int valueNext = 0;
            for (int i=0; i<pLetters.Length; i++){
                valueCurrent = alphabets[Convert.ToString(pLetters[i])];
                if (nextIdx + 1 < pLetters.Length)
                {
                    nextIdx += 1;
                    valueNext = alphabets[Convert.ToString(pLetters[i + 1])];
                }
                else {
                    valueNext = 0;
                }

                if (valueCurrent < valueNext)
                {
                    total = (Math.Abs(total) * -1);
                    total -= valueCurrent;
                }
                else {
                    total += valueCurrent;
                }
            }

            return total;
        }
    }
}

- monika.leslivania January 03, 2023 | Flag Reply


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