Interview Question for SDE-2s

Country: India

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Easiest solution would be to populate a min-heap of size k.

First, populate the heap with the first k elements.

Next, for each element in the stream - check if it is larger than the heap's head, and if it is - pop the current head, and insert the new element instead.

At any point during the stream - the heap contains the largest k elements.

This algorithm is O(nlogk), where n is the number of elements encountered so far in the stream.

- Nits August 29, 2019 | Flag Reply

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