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Hide a name can by declaring it in an enclosed block.It can be accessed using the scope-resolution operator(::)

namespace A {
  char x;
};
 
namespace B {
  using namespace A;
  int x;
};
 
int main() {
  cout << typeid(B::x).name() << endl;
}

Output would be int.

In a member function definition, the declaration of a local name hides the declaration of a member of the class with the same name.
The declaration of a member in a derived class hides the declaration of a member of a base class of the same name.
defnition of function in derived class hides base class version fucntion ..