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It gives compile time error: can not convert from B to A&

@ Please ignore above Qn. here is correct one

output of following Program
class A
{
int n;
public:
virtual void Fun1(int no=10)
{
n = no;
cout<<"A::Fun1"<<n;
}
};

class B
{
int m;
public:
virtual void Fun1(int no=20)
{
m = no;
cout<<"B::Fun1()"<<m;
}
}


int main()
{
B b;
A &a =b;
a.Fun1();
}

output - B::Fun1 10

My be RB forgot to put following in the code

class B: public A

If he is not forgotten then its a compiler error.

at A &a =b;

Looks like they forgot inheritance in the above code. If B is inherited from A then the output is B::Func1.a The confusing part is what happens if its not a reference and just an object of A ?

ie., A a = b; /// in this class object gets sliced and caling
a.func1() would result int A::Func1..

@ above
Sorry guys I forgot to add class B: public A.. assume class B is publicly inherited from A.

I tried compiling and it worked.

case 1:
int main()
{
B b;
A &a =b;
a.Fun1();
getch();
return 0;
}

output : B::Fun1<>10

case 2:


int main()
{
B b;
A a =b;
a.Fun1();
getch();
return 0;
}

output : A::Fun1<>10

shouldn't first output shd be;
cout<<"B::Fun1()"<<m;

B::Fun1() 20

Yes..!! this function will give error. Invalid assignment for the refenece in A &a;