CareerCup

pass a pointer to pointer to foo(), and how do you free that memory in C?

void foo(char** str) {}
...
foo(&str);

Allowed to add new functions?

Hi,
do you guys think that this will work..?

foo( char **pp) {
  static char foo_buffer[80];
  
  /* fill something into foo_buffer  */
  //  ...

  *pp = foo_buffer;
   return;
}

main() {

    char *str;

  foo ( &str);

  printf ("%s\n", str);

}

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void foo( char ** str ){
	*str = (char *)malloc(5*sizeof(char));
	strncpy(*str, "hell", 4 );
	*(*str + 4) = '\0'; 
}

int main(void) {
	
	char * str;
	foo( &str );
	printf("%s\n", str);
	free( str );
	return 0;
}

shouldnt it be just:
void foo(char *str){}
...
foo(&str);

I dont think the double star is needed.