CareerCup

Note Sure:

But this is what i think it should be


printf("%c",str[0]);
i = 1;
while(str[i]){


if (ASCII (str[i]) == ASCII(str[i+1])) // note no such thing as ASCII
{
printf("%c",str[i]);
i++;
}
else
printf("\n%c",str[i++]);

}

void increasestring(char* str)
{
	char* prev = str;
	while(*str)
	{
		if(*str-*prev != str - prev)
		{
			while(prev < str)
			{
				printf("%c", *prev);
				prev++;
			}
			printf("\n");
		}
		str++;
	}

	while(prev < str)
	{
		printf("%c", *prev);
		prev++;
	}
}

Better solution than my previous one

void increasestring2(char* str)
{
	char prev = 0;
	while(*str)
	{
		if(prev==0 || *str-prev == 1)
			printf("%c", *str);
		else
			printf("\n%c", *str);

		prev = *str;
		str++;
	}
}

void increasestring2(char* str)
{
int i=1;
printf("%c",str[0]);
while(str[i])
{
if(str[i-1] + 1 != str[i])
printf("\n");
printf("%c",str[i]);
i++;
}
}

void print(char *s)
{
char ch= *s;
printf("%c",ch);
while(*s++!='\0')
{
if(ch == (*s -1))
{
printf("%c",*s);
ch = *s;
}
else
{
ch = *s;

printf("\n%c",*s);
}
}
}
O(n) time....

In Java

public static void main(String args[]){
   
        String input = "ABCPTXYUQZ";
        int thisChar, prevChar;
        boolean  firstChar = true;
        for(int i=0;i<input.length();i++)
        {
            if(firstChar)
            {
                System.out.print(input.charAt(i));
            }
            else
            {
                thisChar = input.charAt(i);
                prevChar = input.charAt(i-1);
                if(thisChar != prevChar + 1){
                    System.out.print("\n");
                }

                    System.out.print(input.charAt(i));
            }
            firstChar = false;
        }

    }

O(n)

please write the above program in c without pointer variable
and also write the program in java with simlicity

void Printorder(char a[],int n)
{
int i;
for(i=0;i<n;i++)
{
if(i==0)
printf("%c",a[i]);
else if(a[i]==a[i-1]+1)
printf("%c",a[i]);
else
printf("\n%c",a[i]);
}
}

public static void PrintSeqChar(string str)
{
if (str == null || str.Length == 0)
return;

char prv = str[0];
string line = ""+str[0];

for (int i = 1; i < str.Length; i++)
{
if (prv + 1 == str[i])
{
line += str[i];
}
else
{
Console.WriteLine(line);
line = "" + str[i];
}
prv = str[i];
}
Console.WriteLine(line);
}

<pre lang="" line="1" title="CodeMonkey32300" class="run-this">
public class consecChars {

public static void main(String[] args) {

String s = "ABCXYZDDDMOP";
int length = s.length();
for(int i = 0; i < length; i++) {
int t1 = Character.getNumericValue(s.charAt(i));
int t2 = Character.getNumericValue(s.charAt(i+1));
if(t2 == (t1 + 1)) {
System.out.print(s.charAt(i) + " " + s.charAt(i+1) + " ");
i++;
} else {
System.out.println(s.charAt(i));
}
}

}

}
</pre><pre title="CodeMonkey32300" input="yes">
</pre>

void print(const char * str){
   char * prev = NULL, * cur = str;
   while (cur){
     if(prev && *prev +1 == *cur)
        printf("%c",*cur);
     else{
        printf("\n%c",*cur);
     }
     prev++; cur++;
   }
}

This will definately work....
#include <stdio.h>

int main()
{
  char str[20];
  int i;
  scanf("%s",&str);
  printf("%c",str[0]);
  for(i=1;str[i]!='\0';i++)
  {
    if((str[i] == str[i-1]+1) || (str[i] == str[i-1]-1))
    {
      printf("%c",str[i]);
    }
    else
    {
      printf("\n%c",str[i]);
    }
  }
  return 0;
}

string str = "ABCXYZACCDL";
int start = 0;
for(int i = 0;i < str.length();)
{
if(str[i+1] == str[i] + 1)i++;
else
{
cout<<str.substr(start,i-start+1)<<endl;
i++;
start = i;
}
}

void foo(char *str)
{
        int i,j;
        for(i=0;str[i];++i)
        {
                j=i+1;
                while(str[j] && str[j]==str[i]+1)
                {
                        printf("%c",str[i]);
                        i++;j++;
                }
                printf("%c\n",str[i]);
        }
}

Complete code here: ideone.com/okAES

#include<stdio.h>
int main()
{
    char s[]="abcxyzaccd";
    char a=s[0];
    int i=1;
    
    printf("%c",a);
    while(s[i]!='\0')
    {
        if((++a)==s[i])
        {printf("%c",a);i++;}
        else
        {printf("\n%c",s[i]);a=s[i];i++;}
    }
    
    getch();
}

// YAHOO-CAREERCUP.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include<conio.h>


void print(char *x)
{
if(x!=NULL)
{
printf("%c",*x);










































while(*x!='\0')
{
if(*(x+1)==*(x)+1)
{
printf("%c",*(x+1));
x++;
}
else
{
printf("\n");
printf("%c",*(x+1));
x++;
}
}
}
}

int _tmain(int argc, _TCHAR* argv[])
{
char arr[]="abcxyzaccdefxacghijklmbcd";
print(arr);
getch();
return 0;
}

public class PrintConsecutive {
    public void print(char[] chars) {
        for (int i = 0; i < chars.length; ++i) {
            System.out.print(chars[i]);
            int j = i + 1;
            for (; j < chars.length; ++j) {
                if (chars[j - 1] + 1 == chars[j]) {
                    System.out.print(chars[j]);
                } else {
                    break;
                }
            }
            System.out.println();
            i = j - 1;
        }
    }
    
    public static void main(String[] args) {
        PrintConsecutive p = new PrintConsecutive();
        p.print("ABCXYZACCD".toCharArray());
    }
}

In PHP
$string="ABCXYZGHKLMRTUXY";

for($i=0;$i<strlen($string);$i++)
{
$extract=substr($string,$i,1);
$ord_value=ord($extract);
$ord_value=$ord_value+1;
$m=$i;
$extract_another=substr($string,++$m,1);
$ord_value1=ord($extract_another);
if ($ord_value==$ord_value1)
{
echo $extract;
}
if ($ord_value!=$ord_value1)
{
echo $extract,"<br/>";
}
}

public class Strings {
public static void main(String[] args) {
String s = "ABCXYZACCDpPqrfedtsr";

System.out.print(s.charAt(0));
for (int i =1; i<s.length();i++)
{
int ascii1= s.charAt(i-1);
int ascii2= s.charAt(i);
if(ascii1==ascii2-1 || ascii1==ascii2+1)
{
System.out.print(s.charAt(i));
}
else
{
System.out.println();
System.out.print(s.charAt(i));

}

}

}

}

public static String conSequence(String s)
	{
		if(s.length()<=1)
			return s;
		int ascii = s.charAt(0);
		int i = 0;
		while(i<s.length() && s.charAt(i)==ascii)
		{
			System.out.print(s.charAt(i));
			i++;
			ascii++;
		}
		System.out.println();
		return conSequence(s.substring(i,s.length()));

}

Here is my solution in Java. Feel free to make comments.

public static void printInSequence(String str){
		if(str != null){
			char current = '\0', nextExpected = '\0';
			StringBuilder buff = new StringBuilder();
			for(int i = 0; i < str.length(); i++){
				current = str.charAt(i);
				if(nextExpected == '\0' || nextExpected == current){
					buff.append(current);
					nextExpected = (char) (current + 1);
				} else {
					System.out.println(buff.toString());
					buff = new StringBuilder();
					buff.append(current);
					nextExpected = (char) (current + 1);
				}
			}
			System.out.println(buff.toString());
		}
	}