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n is odd.
- doubao October 21, 2013first look at the element A[n/2+1].
if A[n/2 +1] == A[n/2]
search the left part (from 0 to n/2-1) //the number of the left part is odd, so it's where the target is.
else if A[n/2+1] == A[n/2+2]
search the right part (from n/2+3, n-1)// the number of the right part is odd, so it's where the target is
else
return A[n/2];