bebo
BAN USERMore often than not, they wud like to see your cpp + pointers coding skill with this question. So, try to code in cpp/c.
Possible solution:
- count no. of spaces in input ( say x)
- take new array of [strlen(input) + 2x]
- scan from back and move letters to end. If space is encountered, put it accordingly.
similar type question:
compress a string which has multiple spaces in it with single spaces.
- For this, start scanning from 0th position.
~ In both ways, you will have to copy/shift less no. of elements.
If a one to one mapping has to be shown for elements in tree and items in array, then we can XOR the elements of tree (using any traversal) [say X] and then XOR the items in array [say Y] .
if X XOR Y = 0 , then all the items in tree are present 1:1 to that in array.
If we get these n distances in a list and sort them then the first m entires will give us the required result. But since n is O(billions) , sorting wont be a good option.
Keep min heap of m-records and find the max and min of that heap. Take (m+1)th record (say x).
if( x > max ) move to (m+2)
if( x< min || (min<x<max))remove max from heap, put x in place of that, and re-heapify
When all records are finished, the records i heap is the result. or u can do a heapsort at last.
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Its like increasing slope and then decreasing slope. We have to find the highest point.
- bebo September 11, 2011That highest point cud be found out by using binary search, and check if
a[mid-1] a[mid] a[mid+1] is in increasing or decreasing order.
if increasing , move to right half
if decreasing, move to left half
Stopping criteria: a[mid-1] < a[mid] > a[mid+1]