CareerCup

total count of set bits in the given number.

#include <iostream>

using namespace std;

int main()
{

    int powerOfTwo;

     char exit = 'n';

    while(  exit=='n')
    {
        cout << "Enter number :";
        cin>> powerOfTwo;

        if(powerOfTwo==0)
        {
            cout << "Number is 0 only.";
        }
        if(!(powerOfTwo &(powerOfTwo-1)))
        {
            cout<<"Number is Power of 2..."<<endl;
        }
        else{
            cout<<"Number is not power of 2..."<<endl;
        }

        cout << "Do you want to exit ? Y/N" << endl;
        cin >>exit;
    }

    return 0;
}

it is simple no need to use any locking or anything.

public class RCExample
    {
int maxNumber = 100;
        int number = 1;
        public void PrintEven()
        {
            while (number < maxNumber)
            {
                if (number % 2 == 0)
                {
                   // Console.WriteLine(number);
                    Console.WriteLine(Thread.CurrentThread.Name + " " + number + " ");
                    number++;
                }
            }
        }
        public void PrintOdd()
        {
            while (number < maxNumber)
            {
                if (number % 2 != 0)
                {
                 //   Console.WriteLine(number);
                    Console.WriteLine(Thread.CurrentThread.Name + " " + number + " ");
                    number++;
                }
            }
        }

    }

and

Thread evenThread = new Thread(new ThreadStart( raceCondition.PrintEven));
            evenThread.Name = "Even Thread :";
            Thread oddThread = new Thread(new ThreadStart( raceCondition.PrintOdd));
            oddThread.Name = "Odd Thread :";

            evenThread.Start();
            oddThread.Start();

we can use a deadlock where it's negative effects are far less than it's positive effects. Like
If i start my car in the morning, My smart car monitoring system can stumble into deadlock and just wont let me start. Deadlock reasons should be seriously good.
Please provide better example