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I think we can use a hash function for this. The important point is that it is a floating point. So, first write the floating points a exponent functions (e.g; 1003 = 1.003 * 10^{3}). Then uses nested hashmaps (e.g hashmap(integer*exponent, <hashmap(first_decimal, <haspmap(second_decimal,...)>)>). We can do so until we reach a predetermined depth, and just use brute force on the rest.
- rchala December 13, 2013Complexity for searching O(M+L); where 'M' is the depth and 'L' is the length of the list of number at the end to search from.