rajat sadh
BAN USER
- 109
3of 3 votes
AnswersATM has x currency notes of 100 rupee,y currency notes of 500 rupee,and z currency notes of 1000 rupee notes.
- rajat sadh in India
Customer wants to withdraw n amount at any given time. as per bank rules,Customer can not withdraw more than INR.40000/-per transaction.
If ATM is running out of cash it should throw a message that insufficient Balance, Kindly enter multiple of m value of currency note.where m>=4000 and m<=total number of cash available in ATM.
An intelligent banker has found in customer survey that customer prefers to receive more than 5 currency notes 100 rupee,more than 2 currency noes of 500 rupee and rest of the currency notes is of 1000 rupee where ever possible.
If amount is less than 500,customer will receive 100 rupee currency notes. Bankers goal is to tender the minimum number of currency notes to save customer waiting time and increase customer satisfaction by following customer survey.Banker has hired you to program ATM dissaptch function.
FOR Example: Lets ATM has 200 currency notes of 100 rupees,90 currency notes of 500 rupee and 50 currency notes of 1000 rupee.Customer has placed a withdrawal request of Rs 22,200.00. Dispatch function has given him 7 currency notes of 100,3 currency notes of 500 and 20 currency notes of 1000 rupee| Report Duplicate | Flag | PURGE
Adobe SDE1 Algorithm - 18
-1of 3 votes
AnswersThere are three files
- rajat sadh in United States
original.txt,encryption.txt and decryption.txt
original file contains "ABCEZYAR"
it should be encrypt like "12352625118"
and when we decrypt code then original massage should be return "ABCEZYAR".| Report Duplicate | Flag | PURGE
Amazon Software Engineer Intern Algorithm
#include <stdio.h>
int main(void) {
int i,j;
char str[50];
char ch;
gets(str);
ch=getchar();
for(i=0;str[i]!=NULL;i++){
if(str[i]==ch&&(str[i+1]!=ch&&str[i-1]!=ch)){
for(j=i;str[j]!=NULL;j++){
str[j]=str[j+1];
}
}
}
printf("Final String %s",str);
return 0;
}
#include <stdio.h>
int main()
{
int a[]={4,5,6,5,6,7,8,9,10,9,10};
int i=0,first,index=0;
first=a[0];
while(first!=7&&i<11)
{
if(first>a[i+1])
{
--first;
}
else
{
++first;
}
++i;
++index;
}
printf("%d",index);
}
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i gave a solution to interviewer,but he not satisfied.
i add
with each character and when we decrypt msg then skip
and we can get a original msg..but main problem is that if there 2 digit exits for single character then it gives different msg.for example 26 for Z,25 for Y but it gives me 2 for B,6 for F,2 for B,5 for E.
- rajat sadh July 21, 2014