leo.bioeng
BAN USER
SQL Server only answer - the WITH TIES allows for all the records matching highest invoice amount (I understand this solution is not generic, but for shake of completeness):
SELECT TOP(1) WITH TIES * FROM Invoice WHERE year(inv_date) = 2016 ORDER BY inv_amt DESC
RepConnieLavender, Animator at Altera
My name is ConnieLavender . I am working as a Broker associate . I love field work and visiting different places to ...
Repkristenjjimenezk, Analyst at ADP
We Statistical assistants establish and check numerical facts in many different areas of business, government, and industry. Right now I ...
Repseffreyclifford, Area Sales Manager at Achieve Internet
I am a self-motivated office administrator. I am responsible for providing administrative support to office personnel. I have excellent written ...
RepNirvedPerez, abc at 8x8
To make sure a thorough investigation is done if discrepancies occur. Execute the Brand Customer Service standards to meet or ...
Replimachiya788, Associate at ABC TECH SUPPORT
LeviWebber , is a Housekeeping cleaner at Exact Solutions . I am also exploring new things . Mayong Assam tantrik contact number . Housekeepers ...
Repjohnsantana9ytt9, Backend Developer at Accolite software
I am working as a Support service manager at Pro Star Garden Management . I had a different experience while working ...
RepAahnaAllen, AT&T Customer service email at A9
I am a multilingual Judge with 5 years of combined experience in presiding over court proceedings, prosecuting cases, and tirelessly ...
Repcloptonchirsty, Android Engineer at 8x8
Hello, I am an Organic chemist and my all study and degree is complete from New York.Apart from this ...
RepLaylaMoore, Analyst at ADP
I am a skilled content editor with 3 years of excellent service in the communications field. I developed, researched, and ...
Repmarksloan761, Backend Developer at Apache Design
As a Meeting manager at Red Bears Tavern here I am working for approximately ten years . In my daily life ...
RepRilynFreeman, Area Sales Manager at Knewton
Hi my name is Rilyn. Library assistant in Jeans Unlimited company. I help to keep libraries organised and efficient while ...
RepKarlOlson, job tessio at design
I am Karl .Transportation ticket agent, I help plan travel itineraries by suggesting local tourist attractions and places of interest ...
RepCamilaHill, Accountant at ADP
I am a performance-driven leader providing high-level administrative and operational support, coordinating schedules, preparing travel and documents, and exploring Surah ...
RepNancyCramer, Financial Software Developer at Abs india pvt. ltd.
Nancy , an administrative assistant at Libera Inc. to leverage organizational and research skills to support internal and external prayer to ...
Repggroverwmiller, Android Engineer at 247quickbookshelp
Hello I am a Budget officer with 5 years of experience. The Budget Officer implements budgeting and financial record keeping ...
RepYuvaanMoore, abc at 8x8
I have extensive experience as a newspaper reporter, television news reporter, AM radio talk show host and anchorman for major ...
RepOishiGreen, Android test engineer at ABC TECH SUPPORT
I am a results-oriented debt collector with 3 years of experience and knowledge in the leasing/finance sector. I have ...
RepJulianMiller, abc at ABC TECH SUPPORT
I am a professional auditing assistant with extensive experience in handling administrative duties and executive responsibilities associated with both internal ...
RepMairaSmith, Integration Software Engineer at Absolute Softech Ltd
MairaSmith , an Quality Control Assistant with a record of success in developing and implementing new quality control policies and procedures ...
This following solution uses recursion, so that it can properly track a user that connects multiple times, every time being within the 30-min window from the last login.
This is the schema and data I'm using:
(I'm only using the view for clarity; see at the end for the final query that does not require additional commands).
Notice that there are three chained logins for userid 1: 9:00, 9:25 and 9:45. The following query will properly assign the IDs:
Result table:
The stand alone query (no view required) is as follows:
- leo.bioeng December 15, 2017