Devdmitry
I'm looking for a new job. :)
I'm looking for a new job. :)
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If use a sorting then we have an sorted array for O(n^2 log n), so filling matrix by rows or by columns gets as result a sorted matrix by columns and rows.
- Devdmitry September 16, 2014But If we know about the range of numbers that it's a sequence then we can get sorted matrix by calculating an row and column indexes by number in the sequence for O(n).