androidenthusiast
BAN USER
- 1
5of 5 votes
AnswerWhy facebook?
- androidenthusiast in United States
What was the biggest technical problem that you solved?
Do you have any apps on google play?
Give me a scenario where the requirements were ambiguous, what did you do?| Report Duplicate | Flag | PURGE
Facebook Android Engineer Behavioral - 3
0of 0 votes
AnswersDesign Instagram like app end to end
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Facebook Android Engineer design - 11
0of 0 votes
AnswersGiven a string "L*&EVe)))l", write a method which will determine if the input is a palindrome. Ignore all special characters. Uppercase/lowercase should be considered as same.
- androidenthusiast in United States| Report Duplicate | Flag | PURGE
Facebook Android Engineer Java - 6
0of 0 votes
AnswersImagine a room full of people, with only 1 celebrity in the room. Celebrity is defined as a person who does not know anyone, but everyone knows him/her. Write a method who will take array of people and a person as input and return boolean if the person is a celebrity or not.
- androidenthusiast in United States| Report Duplicate | Flag | PURGE
Facebook Android Engineer Java
static String isRectangle(int[][] arr) {
int row = 0;
int col = 0;
int result = 0;
while(row < arr.length - 2) {
if(arr[row][col] == 1 && arr[row + 2][col+2] == 1 && arr[row + 2][col] == 1 && arr[row][col+2] == 1) {
return "YES";
}
row++;
}
row = 0;
while(col < arr.length - 2) {
if(arr[row][col] == 1 && arr[row + 2][col+2] == 1 && arr[row + 2][col] == 1 && arr[row][col+2] == 1) {
return "YES";
}
col++;
}
return "NO";
}
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This will work for any input , not just for "12"
- androidenthusiast November 19, 2017private static void printAllCombos(String query, Map map) { char[] arr = query.toCharArray(); Set result = new HashSet<>(); for(int a = 0; a < arr.length ; a++) { for(int b=a+1; b < arr.length; b++) { String[] a1 = (String[]) map.get(String.valueOf(arr[a])); String[] a2 = (String[]) map.get(String.valueOf(arr[b])); for(int c = 0; c < a1.length ; c++) { for (int d = 0; d < a2.length; d++) { result.add(a1[c]+a2[d]); } } } } Iterator<String> it = result.iterator(); while(it.hasNext()) { System.out.println(it.next()); } }