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findstring(n) = findstring_ac(n) + n * findstring_ac(n-1)
- totohero September 23, 2016where findstring_ac(n) is number of strings consists only of a and c, not b
And
findstring_ac(n) = fa(n) + fc(n) + fcc(n)
where
fa(n) is number of strings consists of a, c and ends with a
fc(n) is number of strings consists of a, c and ends with only one c
fcc(n) is number of strings consists of a, c and ends with double c
and
fa(1) = fc(1) = 1
fcc(1) = 0
fa(n) = fa(n-1) + fc(n-1) + fcc(n-1)
fc(n) = fa(n-1)
fcc(n) = fc(n-1)