Programming Interview Questions

fruktoed

Questions (1)

Comments (2)

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Comment hidden because of low score. Click to expand.

of 0 vote

Improved solution

fun addBinary(addendumLeft: String, addendumRight: String): String {
var i = addendumLeft.length-1
var j = addendumRight.length-1
/* Handling edge cases */
if(addendumLeft.isEmpty() && addendumRight.isNotEmpty())
return addendumRight
else if(addendumRight.isEmpty() && addendumLeft.isNotEmpty())
return addendumLeft
else if(addendumLeft.isEmpty() && addendumRight.isEmpty())
return ""

/* Implementation */
val result = StringBuilder()
var sum = 0
while (i >= 0 || j >= 0 || sum == 1) {

sum += if(i >= 0) addendumLeft[i] - '0' else 0
sum += if(j >= 0) addendumRight[j] - '0' else 0

result.insert(0, sum % 2)

sum /= 2

if(i >= 0)
i--
if(j >= 0)
j--
}

return result.toString()
}

Thanks to GeeksforGeeks

- fruktoed August 14, 2020 | Flag Reply

Comment hidden because of low score. Click to expand.

of 0 vote

My naive implementation. (Kotlin)

fun addBinary(addendumLeft: String, addendumRight: String): String {
var i = addendumLeft.length-1
var j = addendumRight.length-1
/* Handling edge cases */
if(addendumLeft.isEmpty() && addendumRight.isNotEmpty())
return addendumRight
else if(addendumRight.isEmpty() && addendumLeft.isNotEmpty())
return addendumLeft
else if(addendumLeft.isEmpty() && addendumRight.isEmpty())
return ""

/* Implementation */
val result = StringBuilder()
var carryOn = false
while (i >= 0 || j >= 0) {
if(i < 0 || j < 0)
{
val bin = if(j < 0) addendumLeft[i] else addendumRight[j]
if(carryOn) {
if(bin == '1')
result.insert(0,'0')
else {
result.insert(0,'1')
carryOn = false
}
} else
result.insert(0, bin)

} else {
if(addendumLeft[i] == '0' && addendumRight[j] == '1' ||
addendumLeft[i] == '1' && addendumRight[j] == '0') {
if(carryOn)
result.insert(0, '0')
else
result.insert(0, '1')
}
else if(addendumLeft[i] == '1' && addendumRight[j] == '1') {
if(carryOn)
result.insert(0, '1')
else {
carryOn = true
result.insert(0, '0')
}
}
else {
if(carryOn) {
result.insert(0, '1')
carryOn = false
} else
result.insert(0,'0')
}
}

if(i >= 0)
i--
if(j >= 0)
j--
}

if(carryOn)
result.insert(0, '1')

return result.toString()
}

Any more elegant solution?

- fruktoed August 14, 2020 | Flag Reply

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