Prashanth
BAN USER
We can use the binary representation of number start from 0 till the binary representation of the number is less that the given N.
private void genNumber(final int N) {
int k = 0;
while (true) {
int result = Integer.parseInt(Integer.toBinaryString(k));
if (result > N) {
break;
}
System.out.print(result + " ");
k++;
}
}
- 10
RepDarshWilliams, abc at 8x8
Exceptionally dedicated and professional Academic Advisor with a superb record of student support and satisfaction. Read about dua to put ...
- 0
RepLeenFawn, Analyst at A9
I have experience in managing all facets of front office administration, including handling multi-line phone systems, managing schedules, and maintaining ...
- 0
RepHi, I’m Jamie from the Portsmouth USA and I am working as an account manager. I work for a ...
- 0
Repherminanmuller87, Animator at 247quickbookshelp
Hello,I am a literacy teacher. I completed my degree from Chicago and now am a literacy teacher in a ...
- 0
Replindagwingard, Android test engineer at ABC TECH SUPPORT
Hello, my name is Larry and I am a commercial loan officer. We are commercial loan officers who specialize in ...
- 60
RepMelodyTHeckler, abc at ABC TECH SUPPORT
Earned praised for my work lecturing about get love back by vashikaran. Spent childhood promoting art posters in Jacksonville, FL ...
- 0
Repaishadavind7, Analyst at ASU
Being a Route driver I need to go here and there for the reason for delivering things here. I met ...
- 0
Repandreemsims8765, Accountant at 247quickbookshelp
AndreeSims and I am a Clinical social worker.And nowadays I am doing new research like dua to make someone ...
- 20
RepOliveDavin, abc at 8x8
Experienced forester working in the industry for over 3 years. Solid background in the management of private and public forest ...
- 0
Repnormadyen99, Android Engineer at ABC TECH SUPPORT
I am the Directory Assistance Operator responsible for assisting the callers by making calls, supplying phone numbers, advising the on-call ...
- 0
RepAnayAllen, Analyst at 8x8
Exceptional knowledge of mathematical concepts, accounting and finance topics, tax code, and banking principles.I like the topic of how ...
- 0
Repathenajbarnarda, Android Engineer at ABC TECH SUPPORT
I am a graduate in Civil Engineering with nearly 7 years of experience in planning and implementing technical solutions for ...
- 0
RepRoseLeen, abc at 8x8
I am a strongly seasoned and handworking entry level graphic designer with extraordinary creative thinking and project design abilities. I ...
- 0
RepAllegroMiller, abc at A9
I am working as a Courier service in the limanger company. I possess great communication skills, a highly professional attitude ...
- 0
RepEsotaTaylor, abc at 8x8
I am working as a lecturer with exceptional teaching abilities seeking employment in your organization. I have excellent experience in ...
- 0
Repbrianlwarren596, Android Engineer at 247quickbookshelp
Hey my name is BrainWarren and I am working as an Interpreter.my main work is Interpreters and translators convert ...
- 0
Repdelioshorn, Member Technical Staff at Atmel
Attentive Teller Supervisor with 4 years of experience in assisting customers to meet financial needs and referring customers to partners ...
- 0
RepKaiDolern, abc at 8x8
I am knowledgeable and agile legal assistant offering varied experience working as office assistant in a lawyer’s office and ...
- 0
Repstephanielstokes45, Android Engineer at ABC TECH SUPPORT
Hey, my name is Stephanie and I completed all my study from California. And Nowadays I am working as a ...
I am thinking of backtracking solution to this problem.
- Prashanth February 06, 2018private boolean smashable(String word, Stack<String> wordStack, Set<String> dictionary) { int wordLen = word.length(); if (wordLen == 0) { wordStack.add(word); return true; } for (int i = 0; i < wordLen; i++) { String smashedWord = word.substring(0, i) + word.substring(i + 1); if (smashedWord.equals("") || dictionary.contains(smashedWord)) { wordStack.push(word); if (smashable(smashedWord, wordStack, dictionary)) return true; else wordStack.pop(); } } return false; } // Inside Main if(smashable(word, wordStack, dictionary)) { System.out.println(wordStack.toString()); } else { System.out.println("Not Smashable!!!"); }