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Given an integer N, find the Nth number in the fibonacci series. Consider 0 and 1 to be the seed values. In a fibonacci series, each number ( Fibonacci number ) is the sum of the two preceding numbers. The series with 0 and 1 as seed values will go like- 0, 1, 1, 2, 3, 5… .

Input

The first line contains an integer T, depicting total number of test cases. Then following T lines contains an integer N.

Constraints:
1 ≤ T ≤ 50
1 ≤ N ≤ 50

Output

Space separated Nth fibonacci number for each N given in the input

You are asked q queries each of which can be of type 1 or type 2 Type 1 : Report the area of square of side S. Type 2 : Report the area of rectangle of sides L and R.

Input

The first line of the input contains single integer Q.
Next Q line contains the queries.
Each query first contains type of query
if query is of type one you are given a single integer S
if query is of type two you are given two integers L and R

Constraints
1 <= Q <= 25
1 <= T <= 2
1 <= S,L,R <= 1000

Output

Output Q line each containing answer to the asked query

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My marriage was on last month and I am very happy now because i got a perfect partner in my life. Thanks to Nest Matrimony for helping me to find my desired partner.

Arrange the following growth rates in the increasing order.
O(n3),O(1),O(n2),O(nlogn),O(n2logn),Ω(n0.5),Ω(nlogn),Θ(n3),Θ(n0.5)

Hello Everyone, I want to know the functionality between vTable and vptr in C++. I have faced one interview on skype last week and Recruiter told me this question and i was not given the answer. I have checked on google to find it but still, I am confused. Can anyone know or suggest me some more c++ interview question. which is helpful for my upcoming interviews.

There is a function checkPassword() which takes a password and return an int which represents the number of correct characters at the correct position in that password.

Write a function findPassword() which takes a list of passwords and returns the correct password or null if it doesn't find the correct password. It can make calls to checkPassword() function but it is a very expensive function so the goal is to minimize the calls to checkPassword().

Assume all passwords are of same length.

Example:-
If correct password = abcd
calling checkPassword("axyz") would return 1

Sample Input =
String[] passwords = {"xxyz","axyz", "xbyz","abyz","axyd","xycd"}
System.out.println("password = "+findPassword(passwords));

Sample Output:-
password = abcd

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The webmail Bellsouth is the most popular emailing service that is offering the quality, unique, and amazing features for the users. Sometimes, users are passing through some technical problems with their account. A technical blunder is happening with me. I have forgotten my password of Bellsouth, hence I want to reset Bellsouth email password correctly. Resetting the password is a big challenge for me, hence I am getting stuck in the technical procedure. I don’t have the full technical skill on how to reset Bellsouth email password. Can anyone help for this technical blunder?

The question asks us to write a method that tells if one string is a permutation of the other. Looking at the solution it looks like the function tells if 2 strings are anagrams and not permutations. For example the function will return true for "dog" and "dgo". Am I missing something?

Given the code below. I need to replace all occurrences of List<List<Integer>> with List<PairInt>. I could not find this PairInt type/class in a library. Do I need to make a new class and what would that be? Thanks!

public static List<List<Integer>> getIdPairsForOptimal(List<List<Integer>> forwardList,
List<List<Integer>> backwardList, int maxDistance) {
List<List<Integer>> result = new LinkedList<List<Integer>>();
forwardList = forwardList.stream().sorted((x1, x2) -> Integer.compare(x2.get(1), x1.get(1)))
.collect(Collectors.toList());
backwardList = backwardList.stream().sorted((x1, x2) -> Integer.compare(x1.get(1), x2.get(1)))
.collect(Collectors.toList());
int maxDist = maxDistance;
while (true) {
for (List<Integer> l : forwardList) {
for (List<Integer> b : backwardList) {
int forward = l.get(1);
int backward = b.get(1);
int tot = (forward + backward);
if (tot > maxDist) {
break;
}
if (tot == maxDist) {
// print the pair of Id and optimum distance
result.add(Arrays.asList(l.get(0), b.get(0), maxDist));
break;
}

}
}
if (result.size() > 0) {
break;
}
maxDist--;
}
return result;
}

}

I was expecting a bi-directional search of question 1 in this chapter but found a single search in solution, Any reason?

Array Deletion

Mark has an array , A of N elements. He Performs Q queries in it. In each query, he chooses an index I(0-based)
and does the following :

for j=I+1 to N:
if A[j] < A[I]:
A[j] = 0


you need to print what array A looks like after processing all the Q queries.

Note: The queriesare not independentof each other i.e. you need to use the changes array A, for each Query.

Constraints
1 <= T <= 10
1 <= N <= 10^5
1 <= A <= 10^9
1 <= Q <= 10^5

Input

The first line of input has an integer T,denoting the number of test cases. Each test case will consist of 3 lines .
The first line contains 2 space seperated integer, N and Q, denoting the number of element in the arrayand number of queries.
2nd line will have N space seperated integersdenoting the elements in the initial array A.
3rd line will have Q space seperated integers denoting the chosen index in the each query.

Output:

For each test case, output in a seperate line, N space seperated integer denoting the final array A.

Sample Input Output

2
5 2
4 3 4 3 2 4 3 4 0 0
3 2
3 1
3 2 1 3 2 1
2