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This is how I would do it :
Look at it like a tree. Iterate through each element as if it is the one being chosen. Keep a boolean array to check if it is visited or not. If an element is chosen and both it's neighbors have been visited, just iterate to find either the closest left or right one (Go in Order). In case one is, visit the other. Simply do this till you hit a node whose neighbors are visited and there are no elements left [I do this with a loop every time, but you can simply keep a count of the elements too].
- Aditya Tirodkar January 26, 2014